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Please share your CS609 All Current Final Term Papers From 1 March 2014 to 13 March 2014

Assalam O Alaikum!!

Please share your CS609 All Current Final Term Papers From 1 March 2014 to 13 March 2014

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fellows LBA and LSN stands for wat?

LSN  logical sector number

jazak Allah guys 

thanks and jazak Allah....

Q1: Suppose we read the contents of Drive parameter block and get the following information.

Number of reserved blocks=2  

Number of blocks in FAT= 7 

Number of blocks in root directory=32 

Find the number of systems blocks .make the appropriate assumptions when needed.  

Q2: Suppose a disk is divided into two partition and we have read MBR at LBA=0 to get information about primary partition

a) How many bytes of code part we need to skip to get information about primary partition?

b) How many bytes of code part we need to read information?

Can anyone tell me these question's answers plzz!

some of the questions in the moaaz file are very difficult to remember 

i made it easy by keeping all same type of MCQs at one place

this i made fo my self but all of you people can also get benefit from it


Keep remember me in your prayers

keep saying Darood (SALU ALYHE WA ALEHI)


Thank you so much Sultan..

Allah Bless you....

Keep saying Darood (SALU ALYHE WA ALEHI)


Question: -                                                                           


Define the following terms relating to HDD (Hard Disk Drive).


Solution: -


(1)             Block: -

Blocks are the sectors per track, smallest addressable unit in memory; address of block is specified as a unique combination of three parameters.


(2)             Sector: -

Each track can hold many thousands of bytes of data. It would be wasteful to make a track the smallest unit of storage on the disk, since this would mean small files wasted a large amount of space. Therefore, each track is broken into smaller units called sectors.


(3)  Track: -

All information stored on a hard disk is recorded in tracks, which are concentric circles placed on the surface of each platter, much like the annual rings of a tree. The tracks are numbered, starting from zero, starting at the outside of the platter and increasing as you go in. A modern hard disk has tens of thousands of tracks on each platter


(4) Cluster: -

Cluster is the collection of contiguous blocks. User data is divided into cluster, number of blocks within a cluster is in power of 2. Cluster size can be varying depending upon the size of the disk.


    (5) Cylinder: -

Cylinder is a collection of corresponding tracks if track on platter changes so will the tracks on rest of the platters as all the heads move simultaneously



(6) Seek Time: -

While accessing a selected block Time required by the head to reach the particular track/cylinder is called seek time



    (7) Access Time: -

The accumulative time that is required to access the selected block is called access time


 (8) LBA (Logical Block Addressing): -

LBA is the address of relative to the start of physical drive i.e. (absolute).


(9) LSN (Logical Sector Number): -

If the blocks are indexed from the boot block such that the boot block has index = 0. Then this index is called LSN. LSN is relative index from the start of logical drive not the physical drive.


(10) DAP (Disk Address Packet): -

Disk Address Packet is data structure used by extended in 13H services to address a block and other information for accessing the block.


(11) BPB (BIOS Parameter Block): -

BIOS Parameter Block is a data structure maintained by DOS in the boot block for each drive. The boot block is typically a 512 byte block it contain some code and data. The data part constitutes the BPB.


(12) DPB (Drive Parameter Block): -

Beside the BPB there is another data structure can be used equivalently called the DPB. The operating system translates the information in BPB on disk into the DPB which is maintained main memory. This data structure can be accessed using the undocumented services 21H/32H.  




please someone tell , is this answer true??????

Find the root directory sector. Where reserved sector = 1 and sector per FAT = 9. Use appropriate assumption where needed? 5 Marks

 Root DIR Sector: reserved sectors +2 * (size of FAT) = 1 + 2 * 9 = 19

plz current mcqs b upload kr dan


yes,ye answer true hai


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