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CS610 Assignment 01 Spring 2021 Solution / Discussion

CS610

Assignment No 1 Solution

Spring 2021

Requirement 1:

Using a proper probing tool on Command Line Interface (CLI) in your computer/laptop, obtain the route information of www.vu.edu.pk up to 3 hops. Take the complete screenshot containing the related command and the result. Paste the screenshot as your solution in MS Word file.

Solution:

For Task: Run CMD

Input Command: TRACERT -h 5 www.vu.edu.pk

Screen Shot:

 

Requirement 2:

  • Suppose in a shared network of five computers, a 15 MB file is transferred by a computer without breaking down into packets across the network with 56Kpbs capacity. You are required to calculate the time in minutes that it will take to transfer this file.

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CS610 Assignment 1 Solution Spring 2021 || Computer Network || 100% Correct Solution

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CS610-Solution-Assignment-No-1.docx

Question No 1

Using a proper probing tool on Command Line Interface (CLI) in your computer/laptop, obtain the route information of www.vu.edu.pk up to 3 hops. Take the complete screenshot containing the related command and the result. Paste the screenshot as your solution in MS Word file.

Solution

For Task: Run CMD

Input Command: TRACERT -h 5 www.vu.edu.pk

Question No 2(Part 1)

Suppose in a shared network of five computers, a 15 MB file is transfer by a computer without breaking down into packets across the network with 56Kpbs capacity. You are required to calculate the time in minutes that it will take to transfer this file.

Solution

File Size =15MB

15X1000000

=15000000 Byte

=15000000*8 bits

=120000000 bits

Network Speed = 56Kbps = 56*1000 => 56000 bps Time required = 1200000/56000 = 2142.86 second Now convert it minutes

= 2142.86/60

= 35.71 minutes

Question No 2(Part 2)

Now, if the same file is broken into 2000 bytes packets, then you are require to calculate the time in seconds that other computers must wait before beginning of data transfer.

Solution

 Packet Size = 2000 Bytes

= 2000*8 bits =16000 bits

Network speed = 56Kbps = 56*1000 => 56000bps

Time required = 16000/56000

= 0.286 second

Wait for 0.286 second before beginning to transmit.

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CS610 Assignment No 1 Spring 2021 100 % Correct Complete Solution By Abid Farooq Bhutta

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CS610 Assignment No 1 Spring 2021 | Solution | Virtual University Of Pakistan.

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