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CS610 Assignment No 02 Solution & Discussion Due Date: Dec 02, 2016
CS610 - Computer Network Assignment No. 2 Solution Fall 2016 Due Date: Dec 02, 2016
Assignment No. 02 CS610 –Computer Networks |
Total Marks: 20
Due Date: 02-12-2016 |
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Assignment |
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Problem Statement:
Consider the following graph showing switches as nodes with edges.
a) Give the routing table for all 4 switches containing information of destination and next hop. [Marks: 10] b) Give routing table with default routes for the above scenario. [Marks: 10]
Sample Tables:
Default Routes:
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Deadline: Your assignment must be submitted on or before 02-12-2016 |
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&
It is in Lecture No.16
please share solved assignment.
Dear Students Don’t wait for solution post your problems here and discuss ... after discussion a perfect solution will come in a result. So, Start it now, replies here give your comments according to your knowledge and understandings....
Solution-1:
Route Table:
Node 1 |
Node2 |
Node3 |
Node4
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||||
Destination |
Next Hop |
Destination |
Next Hop |
Destination |
Next Hop |
Destination |
Next Hop |
1 |
- |
1 |
(2,1) |
1 |
(3,1) |
1 |
(4,3) |
2 |
(1,2) |
2 |
- |
2 |
(3,1) |
2 |
(4,3) |
3 |
(1,3) |
3 |
(2,1) |
3 |
- |
3 |
(4,3) |
4 |
(1,3) |
4 |
(2,1) |
4 |
(3,4) |
4 |
- |
Solution-2:
Default Table:
Node 1 |
Node2 |
Node3 |
Node4
|
||||
Destination |
Next Hop |
Destination |
Next Hop |
Destination |
Next Hop |
Destination |
Next Hop |
1 |
- |
2 |
- |
3 |
- |
4 |
- |
2 |
(1,2) |
* |
(2,1) |
4 |
(3,4) |
* |
(4,3) |
* |
(1,3) |
|
|
* |
(3,1) |
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Hey chk it... is this corrct r not>>
Route table mein NODE 2 Destination 4 mein i think (1,3) aye ga
No she is right .... (2,1 ) hi aye ga (1,3) ni
i have submitted my assignment .... you can solve this assignment easily by taking lecture 16.
(1,3) aye ga qk 1 tu direct 3 say attach hai
ni pari... hm node 2 ko dekh re hn.. beshhk 1 n 3 se r 3 4 se attach hn.. bt link hm ne 2 ka chk krna ha, wo 1 k sth ho ra ha r phr 3 k sth.. r phr 3 4 k sth
so node 2 k destination 4 k liye hm (2,1) kren ge. bcz 2 one k sth link kr ra ha r 1 3 k n 3 4 k sth.
is this solution is correct.......????
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