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# MGT411 Assignment#02 Solution & Discussion Due Date:26-01-2011

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how u get the result of part 1 , 4.5833 and 3.965, plz explain. in fact u may upload the solution file of question 1 part 1 , coz i cant understand

sorry cant upload it...I suffered alot in past coz  of other students copying exactly..M not blaming anyone but its better to be safe from now on...

As far as 1st part goes..

your formula is  m = [1 + (C/D)] / [(C/D) + Rd + (ER/D)]

C/D is 10% and 15% in second case. Rd is 10% and ER/D is given as 4% .

Do calculations, you will get it.

Regards

BM

DEAR FIND THE ATTACHMENT PLS
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