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MTH100 - General Mathematics Assignment No. 2 Solution and Discussion Spring 2014 of Virtual University (VU) Due Date: July 10, 2014

MTH100 - General Mathematics Assignment No. 2 Solution and Discussion Spring 2014 of VirtualUniversity (VU) Due Date: July 10, 2014

 

Assignment: # 02 (Spring 2014)

 

Mth100 (General Mathematics)

 

Lecture: 19 – 28

Total Marks = 15

Due date: July 10, 2014

 

INSTRUCTIONS:-

 

  1. In order to attempt this assignment you should have full command on Lecture# 19 to Lecture # 28

 

  1. Try to get the concepts, consolidate your concepts and ideas from these questions which you learn in Lecture# 19 to Lecture # 28.
  2. You should concern recommended books for clarify your concepts if handouts are not sufficient.
  3. Try to make solution by yourself and protect your work from other students. If we found the solution files of some students are same then it ‘ll be rewarded zero marks to all those students.
  4. You are supposed to submit your assignment in Word format any other formats like scan images, PDF format etc will not be accepted and will be give zero marks.
  5. Assignments through e-mail will not be accepted after the due date.If there is any problem in submitting your assignment through LMS, you can send your solution file through email with in due date.
  6. You are advised to upload your assignment at least two days before Due date.

 

 

 

 

 

 

 

 

 

 

 

 

Q 1 Write out the expansion of (1 - 2x)7 .

 

Q 2 Are the lines and parallel, perpendicular, or neither?

 

Q 3 Find the exact value of Cos 300o .

 

    

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Replies to This Discussion

Please Discuss here about this assignment.Thanks

Our main purpose here discussion not just Solution

We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.

Example for Q 1


(1 + 2x)^7 ≈ 1 + 14x + 84x^2 + 280x^3 

Letting x = 0.01: 

[1 + 2(0.01)]^7 ≈ 1 + 14(0.01) + 84(0.01)^2 + 280(0.01)^3 
==> (1.02)^7 ≈ 1.14868 

Multiplying both sides by 1.02: 

1.02 * (1.02)^7 ≈ (1.02)(1.14868) 
==> (1.02)^8 ≈ 1.1716536 

Q3

cos(300) 
= cos(300-360) 
= cos(-60) 
= cos(60 
= 1/2

 by finding the reflex value of 300 Degrees (also known as 60 Degrees), and finding the Cosine of that gives you the answer. Because it is in the 4th Quadrant, the Cosine in positive, so whatever you get from Cos 60 is the actual answer, as in you don't need to make it negative. 

360 Degrees is the same as 0 Degrees, in terms of the Unit Circle. To get the Secant, you can do 1 divided by the Cosine of 360. 

Note to those above: He asked HOW to do it, not what the answer is. Nonetheless, the first guy is wrong.

Originally, the Cos and Sin function has a period of π, or 360º. So if you add 360º (for degree) or π (for radian) to the angle value, you get the same value of the function. 

For example: Sin(30º) = Sin(30º+360º) = Sin(30º-360º) = 0.5 
or Sin(-π/6) = sin(-π/6 + π) = -0.5 

So cos(300º) = cos(300º - 360º) = cos(-60º) = 0.5 

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