We have been working very hard since 2009 to facilitate in your learning Read More. We can't keep up without your support. Donate Now.
+ Link For Assignments, GDBs & Online Quizzes Solution 
+ Link For Past Papers, Solved MCQs, Short Notes & More 
DON’T MISS THESE: Important instructions before attempting the solution of this assignment:
• To solve this assignment, you should have good command over 09  13 lectures.
• Upload assignments properly through LMS, No Assignment will be accepted through email.
• Write your ID on the top of your solution file.
Tags:
+ http://bit.ly/vucodes (Link for Assignments, GDBs & Online Quizzes Solution)
+ http://bit.ly/papersvu (Link for Past Papers, Solved MCQs, Short Notes & More)
+ Click Here to Search (Looking For something at vustudents.ning.com?) + Click Here To Join (Our facebook study Group)Please Discuss here about this assignment.Thanks
Our main purpose here discussion not just Solution
We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.
Trigonometric Identities 
(Math  Trig  Identities) 
sin(theta) = a / c  csc(theta) = 1 / sin(theta) = c / a 
cos(theta) = b / c  sec(theta) = 1 / cos(theta) = c / b 
tan(theta) = sin(theta) / cos(theta) = a / b  cot(theta) = 1/ tan(theta) = b / a 
sin(x) = sin(x)
csc(x) = csc(x)
cos(x) = cos(x)
sec(x) = sec(x)
tan(x) = tan(x)
cot(x) = cot(x)
sin^2(x) + cos^2(x) = 1  tan^2(x) + 1 = sec^2(x)  cot^2(x) + 1 = csc^2(x)  
sin(x y) = sin x cos y cos x sin y  
cos(x y) = cos x cosy sin x sin y 
tan(x y) = (tan x tan y) / (1 tan x tan y)
sin(2x) = 2 sin x cos x
cos(2x) = cos^2(x)  sin^2(x) = 2 cos^2(x)  1 = 1  2 sin^2(x)
tan(2x) = 2 tan(x) / (1  tan^2(x))
sin^2(x) = 1/2  1/2 cos(2x)
cos^2(x) = 1/2 + 1/2 cos(2x)
sin x  sin y = 2 sin( (x  y)/2 ) cos( (x + y)/2 )
cos x  cos y = 2 sin( (x  y)/2 ) sin( (x + y)/2 )
angle  0  30  45  60  90 

sin^2(a)  0/4  1/4  2/4  3/4  4/4 
cos^2(a)  4/4  3/4  2/4  1/4  0/4 
tan^2(a)  0/4  1/3  2/2  3/1  4/0 
Given Triangle abc, with angles A,B,C; a is opposite to A, b opposite B, c opposite C:
a/sin(A) = b/sin(B) = c/sin(C) (Law of Sines)

(Law of Cosines) 
(a  b)/(a + b) = tan [(AB)/2] / tan [(A+B)/2] (Law of Tangents)
cos(2x) = cos^2(x)  sin^2(x) = 2 cos^2(x)  1 = 1  2 sin^2(x)
In other words we can “factor” a multiplicative constant out of a limit.
thanx, and plz upload answer of 4th question
© 2020 Created by +M.Tariq Malik. Powered by
Promote Us  Report an Issue  Privacy Policy  Terms of Service
+ Link For Assignments, GDBs & Online Quizzes Solution 
+ Link For Past Papers, Solved MCQs, Short Notes & More 
We are usergenerated contents site. All product, videos, pictures & others contents on vustudents.ning.com don't seem to be beneath our Copyrights & belong to their respected owners & freely available on public domains. We believe in Our Policy & do according to them. If Any content is offensive in your Copyrights then please email at m.tariqmalik@gmail.com or Contact us at contact Page with copyright detail & We will happy to remove it immediately.
Management: Admins ::: Moderators
Awards Badges List  Moderators Group
All Members  Featured Members  Top Reputation Members  Angels Members  Intellectual Members  Criteria for Selection
Become a Team Member  Safety Guidelines for New  Site FAQ & Rules  Safety Matters  Online Safety  Rules For Blog Post