All Current Mid Term Papers Spring 2013 (25 May 2013 ~ 06 June 2013) at One Place
From 25 May 22, 2013 to 06 June 2013 Spring 2013
Current Mid Term Papers Spring 2013 Papers, May 2013 Mid Term Papers, Solved Mid Term Papers, Solved Papers, Solved Past Papers, Solved MCQs
Tags:
Please Share your Current Papers mid Term Papers Spring 2013 Questions/Pattern here to help each other.
Share your today midterm paper here in reply of this discussion
Thanks
mth101 midterm papers chk all pages
mth101
http://vustudents.ning.com/group/mth101calculusandanalyticalgeometr...
Share Your Current mid Term Papers (Questions/Pattern) From 25 May 2013 to 06 June 2013 to help each other. Thanks
mth 101 midterm paper 29.05.2013 time 3:30
Only 4 to 5question from past papers and remaning from book. Paper was conceptual so read properly book.
1) Limt sinx/x=?
2)Cos (8x+5)
3)tan 5-3x option sy select karna tha
agar concept theak ho to paper easily solve ho jata hay.
remember me in ur prayers
Mostly question on concept basis not from past paper.
Raheel thanks for sharing
Attention Related Mid Term papers Spring 2013: All Fellows You don’t need to go any other site for current Mid Term papers Spring 2013, Because All discussed data/sharing of our members in this discussion are going from here to other sites. You can judge this at other sites yourself. So don’t waste your precious time with different links.
What are the critical points of f(x)= x^3+2x^2-4x+5?
to find the critical points of a function, we need to find the first derivative and equal it to zero as the following:
f(x) = x^3+2x^2-4x+5
f ' (x) = 3x^2 + 4x - 4 ===>equal it to zero
0 = 3x^2 + 4x - 4
-b +/- [ sqrt( b^2 - 4*a*c ) ] / [ 2a ]
-4 +/- [ sqrt( 4^2 - 4*3*-4 ) ] / [ 2*3 ]
-4 +/- [ sqrt( 16 + 48) ] / [ 6 ]
-4 +/- [ sqrt( 64) ] / [ 6 ]
[ -4+/- 8 ] / 6 =====> [ -4+8 / 6 ] = 2/3 =====> & [ -4-8 / 6 ] = -2 ( critical points )
Find the equation of the line that passes through (6,5) and (-3, -1).?
First you want to find the slope. The formula is:
y2 - y1 (divided by)
x2 - x1 (the numbers are sub 1 and sub 2, not exponents)
in the first ordered pair (x1, y1) is (6,5). the second (x2, y2) is (-3, -1)
now fill in the formula.
y2 is -1. y1 is 5. So the numerator is -1 minus 5. Which is -6.
x2 is -3. x1 is 6. So the denominator is -3 minus 6. Which is -9.
So our slope is -6/-9 which can be simplified to 2/3.
NOW. You know the slope is 2/3. Now you must find a line with this slope that runs through those points (either set of points will work).
y - y1 = 2/3 (x - x1).
Fill in for y1 and x1 with either set of points (but be consistent. if you use from the first set for x, you must use from the first set for y).
We'll use (-3, -1)
y - -1 = 2/3 (x - -3)
When subtracting a negative, you add. So:
y + 1 = 2/3 (x + 3)
Now distribute 2/3.
y + 1 = 2/3x + 2. (2/3 times 3 is 2)
now subract 1 from both sides.
y = 2/3x + 1
All solved MTH101 past midterm papers in one file
© 2021 Created by + M.Tariq Malik. Powered by
Promote Us | Report an Issue | Privacy Policy | Terms of Service
We non-commercial site working hard since 2009 to facilitate learning Read More. We can't keep up without your support. Donate.
We are user-generated contents & non-commercial site. All product, videos, pictures & others contents on site don't seem to be beneath our Copyrights & belong to their respected owners & freely available on public domains. All Contents on site are for personal & non-commercial use.We believe in Our Policy & do according to them. If Any content is offensive in your Copyrights then please email at m.tariqmalik@gmail.com with copyright detail & We will happy to remove it immediately.
Management: Admins ::: Moderators
Awards Badges List | Moderators Group
All Members | Featured Members | Top Reputation Members | Angels Members | Intellectual Members | Criteria for Selection
Become a Team Member | Safety Guidelines for New | Site FAQ & Rules | Safety Matters | Online Safety | Rules For Blog Post