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plzz koi full solution upload kro
aray bhai koi to kuch clear cut solution uplod kro yar suggestions ni chaiye han
proper solution bhejo dosto
kia koi bi maths ka expert nai idar??????????
Hey folks,
please note:
[f(x) - g(x)]dx
[x^2 - 3x - (-2)]
[x^2 - 3x + 2]
Please note the sign of + before 2.
ali bhai ap ne 3rd last step mein 3/4 ko 4/3 ksey kia hai aur 27/64 q likha hai plz explain
x* ka kia mtlb ha i mean ye kun use kia gya ha
plzzz 1 day left, send full solution of mth-101 assignment-2
ye samajhne ka waqt nahi k kia kyun kese hua bs kuch rad o badal se assignment likh k bhejo sabhi
and to be honest i think koi bi confident nahi hai is sab solutions k baarey mein ajeeb bat hai koi bi mathematician nahi pooray group mein jo certainty se verify ya modify kr sake in suggestions ko so just contented rahein jo hai idar
ali raza marshal bhai agr ap mjhe thoda sa guide kr detey in points k barey main tu ju main ne pehly pochey tu apki bari inayat hoti ..... khair koe baat nahi actually kafi bizi honey ki waja se solution mein nahi de ska.
kon sa points
Question # 3: Marks 5
Find the volume of the spheroid formed by the revolution of the area bounded by the ellipse about the major axis.
Answer
By using parametric form…..
x = aCos t
y = bSin t, 0 ≤ t ≤ π
Which gives the half ellipse with positive y
dx/dt = - aSint
dy/dt = bCos t
V = π∫(aCos t)²(bCos t) dt on [0,π]
Thanks to the symmetry w.r.t y-axis we have
V = 2πa²b∫(Cos t)²(Cos t) dt on [0,π/2]
= (*)
∫(cos t)³ dt = ∫(cos t)(1 - (sin t)²) dt
Substitute
Sin t = u
Cos t dt = du
when t = 0, u = 0
when t = π/2, u = 1
(*)
= 2πa²b ∫(1 - u²) du on [0,1]
A primitive is:
F (u) = 2πa²b(u - (1/3) u³)
Then volume is
V = F (1) - F (0) = (4/3)πa²b
Hence proved.
The volume of a spheroid (of any kind) is
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