We have been working very hard since 2009 to facilitate in your learning Read More. We can't keep up without your support. Donate Now.


+ Link For Assignments, GDBs & Online Quizzes Solution


+ Link For Past Papers, Solved MCQs, Short Notes & More

Dear Students! Share your Assignments / GDBs / Quizzes files as you receive in your LMS, So it can be discussed/solved timely. Add Discussion

How to Add New Discussion in Study Group ? Step By Step Guide Click Here.


Ans file is attached

+ http://bit.ly/vucodes (Link for Assignments, GDBs & Online Quizzes Solution)

+ http://bit.ly/papersvu (Link for Past Papers, Solved MCQs, Short Notes & More)

+ Click Here to Search (Looking For something at vustudents.ning.com?)

+ Click Here To Join (Our facebook study Group)

Views: 893


Replies to This Discussion

ap ko 2nd assignment ka 1st question ka method pata hai

bro ap ko kis question main mushkil ho rhi hai 1 or 2....???

in 1 question simply we hve to write its limits of f(x)

and in 2 question jst put the value of x i.e x=3 in gven eqautions...u will get the answer.


miss sadia can u post the solutio\idea of Question 1. plz

no this is not right answer.we hav to put left and right hand limit in Q1 and in Q2 the solution is according the graph values not by putting value of x = 3.

tO phr right ans kia gh tu btA dE..........

tm sOl hi snd kr dO.........


here is the ans of 1 question...


Hi ,,,
i need a solution of question no 2... plz help me out in that.

Question 02


Check the continuity of f(x) at x=3 for the function defined as


We will Put x=3 in given equation


f(3) = 14 ( For Point At x = 3)


f(x) = 3x + 5

f(3) = 3(3) + 5 = 14    For All Value of X < 3


f(x) = 7 + (21/x)

f(3) = 7 + (21/3)

f(3) = 7 + 7 = 14       For All Value Of  x > 3


So F(x) = 14 At all instant hence Function is Continuous


bro plz write the ans of question no 1


yar assinment ka 1st Q to send ker do plzzzzzzzzzzzzzzzz


miss saida thank u very much. i am very sorry but i am confused about the question. kindly explain it deeply. 


Looking For Something? Search Here

© 2020   Created by +M.Tariq Malik.   Powered by

Promote Us  |  Report an Issue  |  Privacy Policy  |  Terms of Service