MTH 101 SECOND ASSIGNMENT 9 TO 14 LECTURE IS COMMING DUE DATE IS 14 NOVEMBER

[++ CHISHTI ++]

PLEASE START THE DISSCUSSION HERE   

Ans file is attached

[fantastic_life]

ap ko 2nd assignment ka 1st question ka method pata hai

[Sadia Malik]

bro ap ko kis question main mushkil ho rhi hai 1 or 2....???

in 1 question simply we hve to write its limits of f(x)

and in 2 question jst put the value of x i.e x=3 in gven eqautions...u will get the answer.

 

[shahbaz Ahamd]

miss sadia can u post the solutio\idea of Question 1. plz

[Nabila Naz]

no this is not right answer.we hav to put left and right hand limit in Q1 and in Q2 the solution is according the graph values not by putting value of x = 3.

[biLmLik]

tO phr right ans kia gh tu btA dE..........

[biLmLik]

tm sOl hi snd kr dO.........

 

[Sadia Malik]

here is the ans of 1 question...

[24xb0bqs5owto]

Hi ,,,
i need a solution of question no 2... plz help me out in that.
Thanks
Waiting..............,,,,,,,,,,,,,,,,,,,,!

[Kashif Pervez]

Question 02

 

Check the continuity of f(x) at x=3 for the function defined as

 

We will Put x=3 in given equation

 

f(3) = 14 ( For Point At x = 3)

 

f(x) = 3x + 5

f(3) = 3(3) + 5 = 14    For All Value of X < 3

 

f(x) = 7 + (21/x)

f(3) = 7 + (21/3)

f(3) = 7 + 7 = 14       For All Value Of  x > 3

 

So F(x) = 14 At all instant hence Function is Continuous

 



[1wvefvox5qmk8]

bro plz write the ans of question no 1

 

[fida hussain]

yar assinment ka 1st Q to send ker do plzzzzzzzzzzzzzzzz

 

[shahbaz Ahamd]

miss saida thank u very much. i am very sorry but i am confused about the question. kindly explain it deeply.