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Assignment No. 1
MTH 101 (Spring 2013)
Maximum Marks: 15
Due Date: 6th May, 2013
DON’T MISS THESE Important instructions:
Solve the following Absolute Value Problems and write their solutions in both inequality and interval notation.
Question#2 Marks 7
Evaluate the following limit.
(Note: In order to get full marks, do all necessary steps)
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We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.
Assalamu Alaikum kindly please meri help kerdein maine in teenon k solutions kerliye hain per microsoft office main mjhse equations nai horhien plzz batadein k main word main kese maths ki equations likhun
plz come and discuss here.
yeah mare ans b yahe han
@shahzab khan, it is not the correct one, and @Saireen Yousaf if you have the same then both of your answers are not correct.
12/5 ≤ x ≤ 6/5 1st Q ka ans
2nd Q ka
4 < x < 8/3
koi baty ga k interval mein qasy likhty hen jvb baqi ya jvb bilkul correct hen mein ny khud keya hen
Limit waly ka ZERO ans ha
@Zeeshan, don't you think that 2nd one should be in form of x>a or x<-a ? How it can be in the form of 4<x<8/3? (Just to guess)
And in the scenario if you punch in the answers of 1st one in calculator you will get(according to your solution) 2.4≤x≤1.2 (How it can be possible in real world?)
ok thank u zeeshan i solved it again and got the answers
6/5 >= x >=12/5
and interval form is
and the second one is
frnd aur jo limit wala question hy uska answer tu btain evalute limit kaisy solved krain gain