We are here with you hands in hands to facilitate your learning & don't appreciate the idea of copying or replicating solutions. Read More>>
+ Link For Assignments, GDBs & Online Quizzes Solution |
+ Link For Past Papers, Solved MCQs, Short Notes & More |
Assignment No. 1
MTH 101 (Spring 2013)
Maximum Marks: 15
Due Date: 6^{th} May, 2013
DON’T MISS THESE Important instructions:
10 lectures.
Question#1 Marks4+4=8
Solve the following Absolute Value Problems and write their solutions in both inequality and interval notation.
Question#2 Marks 7
Evaluate the following limit.
(Note: In order to get full marks, do all necessary steps)
Tags:
+ Click Here To Join also Our facebook study Group.
..How to Join Subject Study Groups & Get Helping Material?...
+ http://bit.ly/vucodes (Link for Assignments, GDBs & Online Quizzes Solution)+ http://bit.ly/papersvu (Link for Past Papers, Solved MCQs, Short Notes & More)
+ Click Here to Search (Looking For something at vustudents.ning.com?)Please Discuss here about this assignment.Thanks
Our main purpose here discussion not just Solution
We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.
Assalamu Alaikum kindly please meri help kerdein maine in teenon k solutions kerliye hain per microsoft office main mjhse equations nai horhien plzz batadein k main word main kese maths ki equations likhun
plz come and discuss here.
yeah mare ans b yahe han
@shahzab khan, it is not the correct one, and @Saireen Yousaf if you have the same then both of your answers are not correct.
12/5 ≤ x ≤ 6/5 1st Q ka ans
2nd Q ka
4 < x < 8/3
koi baty ga k interval mein qasy likhty hen jvb baqi ya jvb bilkul correct hen mein ny khud keya hen
Limit waly ka ZERO ans ha
zeeshannayab512@gmail.com
@Zeeshan, don't you think that 2nd one should be in form of x>a or x<-a ? How it can be in the form of 4<x<8/3? (Just to guess)
And in the scenario if you punch in the answers of 1st one in calculator you will get(according to your solution) 2.4≤x≤1.2 (How it can be possible in real world?)
ok thank u zeeshan i solved it again and got the answers
6/5 >= x >=12/5
and interval form is
[6/5,-infi)U[12/5,+infini)
and the second one is
8/3<X<4
interval is
(8/3, 4)
frnd aur jo limit wala question hy uska answer tu btain evalute limit kaisy solved krain gain
M.welcome
© 2019 Created by + M.Tariq Malik. Powered by
Promote Us | Report an Issue | Privacy Policy | Terms of Service
We are user-generated contents site. All product, videos, pictures & others contents on vustudents.ning.com don't seem to be beneath our Copyrights & belong to their respected owners & freely available on public domains. We believe in Our Policy & do according to them. If Any content is offensive in your Copyrights then please email at m.tariqmalik@gmail.com or Contact us at contact Page with copyright detail & We will happy to remove it immediately.
Management: Admins ::: Moderators
Awards Badges List | Moderators Group
All Members | Featured Members | Top Reputation Members | Angels Members | Intellectual Members | Criteria for Selection
Become a Team Member | Safety Guidelines for New | Site FAQ & Rules | Safety Matters | Online Safety | Rules For Blog Post