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Assignment No. 2
MTH 101 (Spring 2013)
Maximum Marks: 15
Due Date: 9^{th} July, 2013
DON’T MISS THESE Important instructions:
Ø To solve this assignment, you should have good command over
Lectures 30 to 35.
Only MS-Word file is acceptable for the solution of assignment. No other format is acceptable.
Question#1 Marks 7
Evaluate the integral
Question#2 Marks 8
(Note: In order to get full marks, do all necessary steps)
GOOD LUCK!
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We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.
Q2 ans
pt of intrsctn of graph is at +ve x-axis is at 1 & intrvls are i.e., value of x lies b/w [0,1]
use volume formula in intgral wth gvn intrl n hve ans
Best of luck
I hope now it wil b easy for all of You
Draw Graph othrwise instrctr kiya pta k kahien ka gusa kahein na utar dein aur no ap k kaat dy
Rab jany k Volume of cylndr parhaya b hy ap ko ya drct questn dy diya
go through lec 33+ n chk for volumes of cylndr
Remembr ALL Muslims in ur pryrs along with non muslims that ALMIGHTY ALLAH put them all on right path
given intrvls are on x axis [0,1], now how can we make a graph without having y axis values bcz 0,1 lies only on x axis makes no sense of any graph without y axis values
ara y baba y=0 ye intrvls intgral ki upr lower limits hain n ths is cylindricl shell case so woh frula use karein just ye crcle ka nai
bst of luck
The Volume Of Solid ...Obtained By Rotating About y-axis the region under curve y=f(x) from a->b, is given above
As it Soundz tht "The point Of intersection at +ve x-axis is at x=1(bcz as x->1 thn y->0) so it will intersect at x=1) So interval is [0,1] mean x varry from 0 to 1 or in other words b=1 & a=0"
I hope this will help little bid
Best Of Luck
This assignment is easy
Idea for
Q 2 i thnk to eq. r
y=1-x^2 & y=0(bcz at x-axis y=0)
so on solvng 0=1-x^2 => x^2=1 => so x = 1 & x=-1 => y=0 now furthr solve by ur self
best of luck
kya ye 100 % correct hai kya ???????????
Y=0 Now y ki dosary value kiya hogi?
@x=1
y = 1-x^2 = 1-1 = 0
now @x = -1
y = 1-x^2 = 1-(-1)^2 = 1-1 = 0
y is again equal to 0
how can it possible???
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