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Assignment No. 2
MTH 101 (Spring 2013)
Maximum Marks: 15
Due Date: 9^{th} July, 2013
DON’T MISS THESE Important instructions:
Ø To solve this assignment, you should have good command over
Lectures 30 to 35.
Only MS-Word file is acceptable for the solution of assignment. No other format is acceptable.
Question#1 Marks 7
Evaluate the integral
Question#2 Marks 8
(Note: In order to get full marks, do all necessary steps)
GOOD LUCK!
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Q2 ans
pt of intrsctn of graph is at +ve x-axis is at 1 & intrvls are i.e., value of x lies b/w [0,1]
use volume formula in intgral wth gvn intrl n hve ans
Best of luck
I hope now it wil b easy for all of You
Draw Graph othrwise instrctr kiya pta k kahien ka gusa kahein na utar dein aur no ap k kaat dy
Rab jany k Volume of cylndr parhaya b hy ap ko ya drct questn dy diya
go through lec 33+ n chk for volumes of cylndr
Remembr ALL Muslims in ur pryrs along with non muslims that ALMIGHTY ALLAH put them all on right path
given intrvls are on x axis [0,1], now how can we make a graph without having y axis values bcz 0,1 lies only on x axis makes no sense of any graph without y axis values
ara y baba y=0 ye intrvls intgral ki upr lower limits hain n ths is cylindricl shell case so woh frula use karein just ye crcle ka nai
bst of luck
The Volume Of Solid ...Obtained By Rotating About y-axis the region under curve y=f(x) from a->b, is given above
As it Soundz tht "The point Of intersection at +ve x-axis is at x=1(bcz as x->1 thn y->0) so it will intersect at x=1) So interval is [0,1] mean x varry from 0 to 1 or in other words b=1 & a=0"
I hope this will help little bid
Best Of Luck
This assignment is easy
Idea for
Q 2 i thnk to eq. r
y=1-x^2 & y=0(bcz at x-axis y=0)
so on solvng 0=1-x^2 => x^2=1 => so x = 1 & x=-1 => y=0 now furthr solve by ur self
best of luck
kya ye 100 % correct hai kya ???????????
Y=0 Now y ki dosary value kiya hogi?
@x=1
y = 1-x^2 = 1-1 = 0
now @x = -1
y = 1-x^2 = 1-(-1)^2 = 1-1 = 0
y is again equal to 0
how can it possible???
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