We are here with you hands in hands to facilitate your learning & don't appreciate the idea of copying or replicating solutions. Read More>>

Looking For Something at vustudents.ning.com? Click Here to Search

www.bit.ly/vucodes

+ Link For Assignments, GDBs & Online Quizzes Solution

www.bit.ly/papersvu

+ Link For Past Papers, Solved MCQs, Short Notes & More

MTH101 - Calculus And Analytical Geometry Graded Discussion Board(GDB) Closing Date Monday, May 23, 2016

+ Click Here To Join also Our facebook study Group.

+ How to Join Subject Study Groups & Get Helping Material?

+ How to become Top Reputation, Angels, Intellectual, Featured Members & Moderators?


See Your Saved Posts Timeline

Views: 1734

.

+ http://bit.ly/vucodes (Link for Assignments, GDBs & Online Quizzes Solution)

+ http://bit.ly/papersvu (Link for Past Papers, Solved MCQs, Short Notes & More)

+ Click Here to Search (Looking For something at vustudents.ning.com?)

Replies to This Discussion

Please Discuss here about this GDB.Thanks

Our main purpose here discussion not just Solution

We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.

MTH101 - Calculus And Analytical Geometry GDB No. 1 Solution Spring 2016 Due Date May 23, 2016

MTH101 - Calculus And Analytical Geometry GDB No. 1 Solution Spring 2016 Due Date May 23, 2016

For f(x)  = x2+1 and g(x) = x2,find the composition fg and gf and identify the domain of each.Note: Domain of a function means those values of x at which both compositionare not undefined.

smjhaaa b dein bhai isay

mth101 gdb solution

Attachments:

IDEA SOLUTION ATTACHED

Attachments:

Given f(χ) = χ²+1

g(χ) = χ-²



f∘g = (f∘g) (χ) = f(g(χ))

Putting values

=f(√χ-2)

=(√χ-2)²+1

=χ-2+1

=χ-1

Domain= (-∞,∞)



g∘f = (g∘f) (χ)

g = g(f(χ))

= g(χ²+1)

= √(χ²+1) - 2

= √(χ²-1) 

Domain = (-∞,-1] , ∪ [1,∞)

thankssss Alot,,,

math type ma square kase lete ha

Correct Solution of mth101 GDB is here
http://machinefreak.com/mth101-gdb-no1-solution

RSS

© 2019   Created by + M.Tariq Malik.   Powered by

Promote Us  |  Report an Issue  |  Privacy Policy  |  Terms of Service