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# MTH101 GDB Discussion & Solution Due Date 25-01-2012

Describe in your own words about the graph where the function becomes

1)      Discontinuous at a point.

2)      Continuous but not differentiable at a point.

Note: Do not paste graph/images to explain it.

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### Replies to This Discussion

1) Discontinuous at a point

It means that a function y = f(x) is not defined at some point. Usually such a function possesses vertical asymptotes at such point. If we take the example of a function y = 1/x. We knoe that when x=0, then we get zero in the denominator and division by zero is not allowed, therefore, graph of y = 1/x has discontinuity at x = 0. Also, it possesses a verticle asymptote x = 0.

2) Continuous but not differentiable at a point

Usually such points are of closed shapes e.g. circle, ellipse, etc. etc. Such graphs are continuous at its left most and right most end on the x-axis, but are not differentiable at that point. y = Sqrt(1-x^2) is one such function which is continuous at x = 1 but not differentiable at x = 1.

Very nice sir

Calculus Lover gud keep it up

please explain 2nd point ...i dnt understand ..

Thanks..

check the attachment

Attachments:

Please Discuss here about this GDB.Thanks

Announced GDB Topic:

Describe in your own words about the graph where the function becomes

1) Discontinuous at a point.

2) Continuous but not differentiable at a point.

Note: Do not paste graph/images to explain it.

Opening Date: January 24, 2012 at 12:01 AM

Closing Date: January 25, 2012 at 11:59 PM

Solution:

1) Discontinuous at a point
It means that a function y = f(x) is not defined at some point. Usually such a function possesses vertical asymptotes at such point. If we take the example of a function y = 1/x. We knoe that when x=0, then we get zero in the denominator and division by zero is not allowed, therefore, graph of y = 1/x has discontinuity at x = 0. Also, it possesses a verticle asymptote x = 0.
2) Continuous but not differentiable at a point
Usually such points are of closed shapes e.g. circle, ellipse, etc. etc. Such graphs are continuous at its left most and right most end on the x-axis, but are not differentiable at that point. y = Sqrt(1-x^2) is one such function which is continuous at x = 1 but not differentiable at x = 1.

MTH101 GDB IDEA SOLUTION FALL 2012

thx1) Discontinuous at a point
It means that a function y = f(x) is not defined at some point. Usually such a function possesses vertical asymptotes at such point. If we take the example of a function y = 1/x. We knoe that when x=0, then we get zero in the denominator and division by zero is not allowed, therefore, graph of y = 1/x has discontinuity at x = 0. Also, it possesses a verticle asymptote x = 0.
2) Continuous but not differentiable at a point
Usually such points are of closed shapes e.g. circle, ellipse, etc. etc. Such graphs are continuous at its left most and right most end on the x-axis, but are not differentiable at that point. y = Sqrt(1-x^2) is one such function which is continuous at x = 1 but not differentiable at x = 1.thnx

MTH101 GDB IDEA SOLUTION FALL 2012

thx1) Discontinuous at a point
It means that a function y = f(x) is not defined at some point. Usually such a function possesses vertical asymptotes at such point. If we take the example of a function y = 1/x. We knoe that when x=0, then we get zero in the denominator and division by zero is not allowed, therefore, graph of y = 1/x has discontinuity at x = 0. Also, it possesses a verticle asymptote x = 0.
2) Continuous but not differentiable at a point
Usually such points are of closed shapes e.g. circle, ellipse, etc. etc. Such graphs are continuous at its left most and right most end on the x-axis, but are not differentiable at that point. y = Sqrt(1-x^2) is one such function which is continuous at x = 1 but not differentiable at x = 1.thnx

Discontinuous at a point It means that a function y = f(x) is not defined at some point. Usually such a function possesses vertical asymptotes at such point. If we take the example of a function y = 1/x. We know that when x=0, then we get zero in the denominator and division by zero is not allowed, therefore, graph of y = 1/x has discontinuity at x = 0. Also, it possesses a vertical asymptote x = 0. 2) Continuous but not differentiable at a point usually such points are of closed shapes e.g. circle, ellipse, etc. etc. Such graphs are continuous at its left most and right most end on the x-axis, but are not differentiable at that point. y = Sort (1-x^2) is one such function which is continuous at x = 1 but not differentiable at x = 1.

sanasunny gud keep it up

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