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# cheack solution

if u found any mistake then correct it and notify me....

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correctly done!

question my hy k above seys ko use kr k is proprty ko verify kry...then we will use set like (A-B)-C=(A-C)-B Both sides have ans 11.try this

thanks for solution

1 ko prime number consider karain gy ya nai?????????????????

Tariq bhi yai bta dyn k 2nd questn man kryn gy k nai

no...1 is not a prime num...handouts my yai likha hy

thanx 4 sol nyce attempt but last question smj nai ae wo kesay kia?

Assigenment No 2 MTH202

Spring 2013

p = “You are a truthful and honest person.”

q = “People like and respect you.”

Conditional:-
If you are a truthful and honest person then people like and respect you.

Biconditional:-
You are a truthful an honest person if and only if people like and respect you.

Inverse:-
If you are not a truthful and honest person then people do not like and respect you.

Converse:-
If people like and respect you then you are a truthful and honest person.

Contra-Poitive:-
If people do not like and respect you then you are not a truthful and honest person.

(i) Write the given sets A, B and C into Tabular form.

A = {2,3,5,7,11}
B = {1,2,3,4,5}
C = {1,3,5,7,9}

Qno2)

A={2,3,5,7,11}

B={1,2,3,4,5}

C={1,3,5,7,9}

A-B= {2, 3, 5, 7,11}-{1,2, 3, 4, 5}

={11,7}

(A – B) – C = {11,7}-{1, 3,5 ,7,9}

= { 11}................................1

(A – C) ={2,3,5,7,11} - {1,3,5,7,9}

= {2,11}

(A – C) – B= {2,11} - {1, 2, 3, 4, 5}

= {11 }.............................II

Hence L.H.S =R.H.S

Qno 3)

Define a relation R on A as for xRy x divides y.

Then R will be
Solution:-vulearners.com
R={(2,2).(2,4).(2,6).(2,8 ).(3,3).(3,6).(4,4).(4,8 ) (5,5) (6,6) (7,7) (8,8)}

(i) Write the relation R in tabular form
Solution:-
R={(2,2).(2,4).(2,6).(2,8 ).(3,3).(3,6).(4,4).(4,8 ) (5,5) (6,6) (7,7) (8,8)

(ii) Determine whether the relation is reflexive or not.
Solution:-
Yes,
Since there are (2,2) (3,3) (4,4) (5,5) (6,6) (7,7) (8,8) are present so
This is reflexive.

Thankssssssss

3rd question ko plzzzz koi explain ker day

Thankoooo

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