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# Assignment # 2 MTH301 (Spring 2012) Due Date: May 02, 2012

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this is the idea solution if anyone find any mistake then plzzz comment

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dear i can't uderstand that how did you take you value 0 of fx(1,4) = 2lnxy while its value comes 2.7725 becoz

value of ln4 = 1.3862 and 2 * 1.3862 = 2.7725

fx(x,y)=y^2/x.because this is the derivative of f(x,y) with respect to X.then we will put the value fx(1,4).so we get 16.on the other hand when we take then derivative with respect to y we get fy(x,y)=2ylnx after putting the values fy(1,4)=0 because lnx=ln1=0.

okay this is my mistake , you are right

yes I've already shared my solution file of Assignment # 2 and i think you have also gave a comment under my solution discussion any how this is the link of my assignment visit it now

http://vustudents.ning.com/group/mth301calculusii/forum/topics/solv...

See the attached file please

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