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GDB # 2 Dated: May 25, 15

Dear Students,

A new GDB has been created and it will be open from May 26, 2015. Due date of the discussion board is May 28, 2015.

From today "Test Math Type” MDB will be closed and you will not allow posting your reply on regular MDB. 

Moreover a new functionality (Preview) has been added in GDB to verify that your post is correctly displaying. So before posting your comments you should first preview your post and if the equations are correctly displaying then you can post the comment. Remember once you post the comments on GDB then you cannot edit or repost your comment.

Question:

Differentiate the following function with respect to t.

 

Grading criteria will be as follows:

  1. If all the  derivatives are calculated correctly, you will get  25% marks
  2.     Moreover if you correctly apply chain rule, you will get 50% marks
  3. If there is calculation/simplification mistake in final calculation, you will get 75% marks
  4. If you express the final equation in terms of ‘t’ , you will get 100% marks

Note: It is mandatory to mention all necessary calculation steps to get full marks.

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Replies to This Discussion

then  what about chain rule?

dw/dx=2x-y

dw/dy= 2y-x

dx/dt=12t^2

dy/dt=-sint

dw/dt=(dw/dx)(dx/dt)+(dw/dy)(dy/dt)

(2x-y)(12t^2)+(2y-x)(-sint)

substituing values of x and y

=96t^5-12t^2cost-2costsint+4t^3sint

MTH301 GDB FINAL and complete 

see the attached file 

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