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|GDB No.3||Dated: Jul 14, 15|
A new GDB has been created and it will be open from July 15, 2015. Due date of the discussion board is July 24, 2015.
Moreover a new functionality (Preview) has been added in GDB to verify that your post is correctly displaying. So before posting your comments you should first preview your post and if the equations are correctly displaying then you can post the comment. Remember once you post the comments on GDB then you cannot edit or repost your comment. Don't post your GDB reply on regular MDB.
Important Note: A new functionality (Preview) has been added in GDB to verify that your post is correctly displaying. So before posting your comments you should first preview the post and if the equations are correctly displaying then you can post the comment. Remember once you post the comments on GDB then you cannot edit or repost your comment.
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Need Solution Please..... Koi Ha Laiq Bacha,
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y=0 mean right side of y or upper region of quadrant or positive side of y?
y is varying from 0 to sqrt(1-x^2)
y = sqrt(1-x^2) is a circle centered at (0,0)
for y = 0, this circle will be to the right of y axis because x is also varying from 0 to 1. Had x varied from -1 to 1, then it was going to be half circle above x axis. However, x is varying from 0 to 1 i.e. one fourth of a complete circle.
Thanks Bro i got your point..
Wow Bro that was awesome Thanks.