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# MTH 301 Calculus II . Assignment No 2. Virtual University . Due Date Jul 17,2014.

Total marks: 20

Lecture # 23 to 30

Due date: July 17, 2014

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### Replies to This Discussion

Arshad Bhai, In fourth line of Q3 correction is required.......

Answer # 1:

Equation of the curve in polar co-ordinates is r2=-4sin2θ

(i) Symmetry about the Initial Line.
r2=-4sin2θ
Remember that sine is an odd function
Put (r,-θ) in equation
r2=-4sin2 (-θ)
r2=-4sin (-2θ)
r2=4sin2θ
This equation is not symmetry about initial line
(ii) Symmetry about the Pole
r2=-4sin2θ
Put (-r, θ) in equation
(-r) 2 =-4sin2θ
r2=-4sin2θ
This equation is symmetry about pole

rdrdθ ko dudθ main q convert kia haiiiiiiiiiiiiii???????????????????

orye question bilkul thk hai....???

Q:1:- Equation of the curve in polar co-ordinates is =-4sin2 discuss the symmetry of graph of this curve about.

1. Initial line
2. Pole

Equation of the curve in polar co-ordinates is

=-4sin2θ

1. Symmetry about the Initial Line.
=-4sin2θ
sin is odd function.
Put (r, -θ) in equation
=-4sin2 (-θ)
=-4sin (-2θ)
=4sin2θ
this equation is not symmetry about initial line
2.  Symmetry about the Pole
=-4sin2θ
Put (-r, θ) in equation
=-4sin2θ
=-4sin2θ
This equation is symmetry about pole

Check it

Attachments:

Q:1:- Equation of the curve in polar co-ordinates is =-4sin2 discuss the symmetry of graph of this curve about.
Initial line
Pole

Equation of the curve in polar co-ordinates is
=-4sin2θ
Symmetry about the Initial Line.
=-4sin2θ
sin is odd function.
Put (r, -θ) in equation
=-4sin2 (-θ)
=-4sin (-2θ)
=4sin2θ
this equation is not symmetry about initial line
Symmetry about the Pole
=-4sin2θ
Put (-r, θ) in equation
=-4sin2θ
=-4sin2θ
This equation is symmetry about pole

MTH301_Complete_Solution

Attachments:

Tariq Bro, you have uploaded two solution for 3rd question which one is correct?

Doc file solution or above mentioned?

Plz ans.....

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