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# Mth301-1st assignment October2011

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i post solution this assignment in last post. so plz chek that

final answer is correct i.e. function is indeed continuous at (0,0) BUT the way limit has been calculated is WRONG. 0/0 is not equal to zero. It is an indeterminate form. To calculate the limit, we will have to approach from 3 different paths which are x=0, y=0, and y=x

u r right bros:

o/1=0

0/x=0

0/y=0

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