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            Total marks: 10

             Lecture # 1 to 8  

Due date: October 25, 2011

 

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Question 1:

 

Convert the given spherical coordinates to rectangular and cylindrical coordinates.

 

 

 

 

Question 2:

 

Determine whether the following limit exists

 

 

 

 

Question 3:

 

Check the continuity of function at (0, 0)

 

 

 

Question # 4

 

Calculate  by using chain rule of differentiation.

Where   and

 

 

Question 5:

 

Calculate the value of  if 

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Please send MTH301 Q3. Solution if you have done it and sure that it's correct.

thanks

Dear Mr. Shahbaz

 

Please send me Q3. pLZZZZZZZ

bc080401773@vu.edu.pk

the answer which has already been posted by me is true

which one i can't find it. Please send it's link

@shehbaz .....in the Q5 when ve take the double partial derivative by keeping y constant then "y" becomes zero n only left is "x" so how can we put(1,1) values??? as there is only x ????

if there is no y, then simply put x=1.

when y become zero(0) then 6x^2 will be left then put the value of x and answer will be 6 

 

[Image: 2a8hoaq.jpg]

final answer is correct i.e. function is indeed continuous at (0,0) BUT they way limit has been calculated is WRONG. 0/0 is not equal to zero. It is an indeterminate form. To calculate the limit, we will have to approach from 3 different paths which are x=0, y=0, and y=x

your question is wrong my brother

to whom you said that?

i think u r right calculus lover

why any one is not calculating the third point function along the line y=x?

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