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Total marks: 10
Lecture # 1 to 8
Due date: October 25, 2011
DON’T MISS THESE Important instructions:
Question 1:
Convert the given spherical coordinates to rectangular and cylindrical coordinates.
Question 2:
Determine whether the following limit exists
Question 3:
Check the continuity of function at (0, 0)
Question # 4
Calculate by using chain rule of differentiation.
Where and
Question 5:
Calculate the value of if
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+ Click Here to Search (Looking For something at vustudents.ning.com?)Please send MTH301 Q3. Solution if you have done it and sure that it's correct.
thanks
Dear Mr. Shahbaz
Please send me Q3. pLZZZZZZZ
bc080401773@vu.edu.pk
the answer which has already been posted by me is true
which one i can't find it. Please send it's link
@shehbaz .....in the Q5 when ve take the double partial derivative by keeping y constant then "y" becomes zero n only left is "x" so how can we put(1,1) values??? as there is only x ????
if there is no y, then simply put x=1.
when y become zero(0) then 6x^2 will be left then put the value of x and answer will be 6
final answer is correct i.e. function is indeed continuous at (0,0) BUT they way limit has been calculated is WRONG. 0/0 is not equal to zero. It is an indeterminate form. To calculate the limit, we will have to approach from 3 different paths which are x=0, y=0, and y=x
your question is wrong my brother
to whom you said that?
i think u r right calculus lover
why any one is not calculating the third point function along the line y=x?
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