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Here is the Solution file of first assignment of MTH301 Download Attachment 

Note: this is the only idea of Solution 

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Replies to This Discussion

Any difficulty in this Solution of Assignment then ask to me 

bhai is assibnment ka first ans or last ans q nea solved kya ap na ... 2nd toh yar ma na kya hua ha solved phly be ....

wo is lye nhi kia q k wo non graded hain aur hum ne sirf 2nd question hi solve kar k send karna hia 1st and last nhi 


Waqas Ahmed i found your solved  file in word format at other network. I want to upload this here.


this is same as my solved file ! and this is against to the copy right now tell me that what can i do?

See the attached file for one more idea solution of MTH301 Assignment#1 Spring 2012


 M.Tariq Malik bhai in last step we have 1/ 1+m^2

if we take m=1 then f(x,y)= 1/2 at every point of the line y=x other than (0,0) .

if we take m= -1 then f(x,y)= 1/2 at every point of the line y= -x other than (0,0) .

thus f(x,y) assumes two same values as (x,y) approaches (0,0) along two different paths.

so limit exist...  now em confused .. according to dis rule ( bsc book chap# 2, 2.6 exercise)  limt exist. or ap ne kha k constant hay is lye limit nai exist krti.. ab ap plzzz mujhy confirm btaye k limt exist krti hy ya nai ta k me apni assignment complt kr sakon 


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