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# Assignment # 2 MTH302 (Spring 2010)

Assignment #  2

MTH302 (Spring 2010)

Total marks: 13

Lecture # 9 to 16

Due date: 17-05-10

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• Question # 2, 3, 4, 5, 6 and 7 doesn’t have any marks, it is for your pre-assessment, solve it, see its solution (when uploaded) but you need not include these questions in solution file.

Question 1:                                                                                                  Marks 08

A flying company offers trips in Europe. The company flies three kinds of airplanes: the Boeing 757, the Boeing 767, and the Boeing 777. Each plane is outfitted with tourist, economy, and first-class seats. In Boeing 757, there are 50 tourist, 30 economy, and 32 first class seats. . In Boeing 767, there are 75 tourist, 45 economy, and 50 first class seats.

In Boeing 777, there are 40 tourist, 25 economy, and 30 first class seats.

The number of reservations for its January flight to Germany, 305 reservations for tourist class, 185 Economy class, and 206 first class.

To fill all the seats how many of each kind of plane should the company fly?

Question: 2                                                                                                  Marks 0

Why the inverse of following matrix is not possible

Question: 3                                                                                                           Marks 0

Write all the steps which are necessary to calculate the inverse of following matrix in Ms Excel and then also write the inverse matrix of given matrix.

Question 4:                                                                                                        Marks 0

Discuss the importance of determinant of a matrix in evaluation of its inverse. Also state at least two properties of determinants which help in their evaluation.

Question 5:                                                                                                         Marks 0

Find amount of markup and selling price on an item that costs Rs. 2400 if there is a 40% markup on cost.

Question 6:                                                                                                         Marks 0

An item sells for Rs. 3200. If the markup on the cost is 48%, find the cost and the amount of the markup.

Question 7:                                                                                                       Marks 0

Find the single discount rate that is equivalent to the series discount of 5%, 7% and 11%.

Question 8:                                                                                                       Marks 05

An item that cost Rs. 2300 was marked up 38 % of the selling price.  After some time the item is markdown 30 %.  Calculate the sale price after markdown.

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### Replies to This Discussion

invers of A is
-1 2.5 -.75
1 -2.2 o.5
-.6 1 0
multiply this matrix with matrix
305
285

206
nadeem bhai time is short for this assignment can you plz send me the solution on my yahoo id ..pzlpzlpzlzplzplzplzpzlpz
billy_us2005@yahoo.com
me tooooooooooooooo!!!!!!!
umarock85@gmail.com
and me too mate
ushibaba@gmail.com
bc100200897@vu.edu.pk

I'll be thankful
did u get the point
Dear, dont u think question no. 1 of assignment was out of course which was from Lec. No 9 to lec. No. 16 while simultaneous equations are taught in later lectures. I have send a mail to subject instructor.
Question 1: Marks 08

A flying company offers trips in Europe. The company flies three kinds of airplanes: the Boeing 757, the Boeing 767, and the Boeing 777. Each plane is outfitted with tourist, economy, and first-class seats. In Boeing 757, there are 50 tourist, 30 economy, and 32 first class seats. . In Boeing 767, there are 75 tourist, 45 economy, and 50 first class seats.
In Boeing 777, there are 40 tourist, 25 economy, and 30 first class seats.
The number of reservations for its January flight to Germany, 305 reservations for tourist class, 185 Economy class, and 206 first class.
To fill all the seats how many of each kind of plane should the company fly?

Solution:

Let we assume:
Boeing 757 be ‘x’
Boeing 767 be ‘y’
Boeing 777 be ‘z’

x y z Total seats
Tourist 50 75 40 305
Economy class 30 45 25 185
First class 32 50 30 206

We have got three equations:

50x + 75y +40z = 305 ………….. (1)
30x + 45y+ 25z= 185 …………… (2)
32x+ 50y+ 30z = 206 …………… (3)

solving equation (1) & (2)

50x + 75y +40z = 305
30x + 45y+ 25z= 185
multiply equation (1) by 3, and equation (2) by -5, we will get:

150x+ 225y+ 120z = 915
-150x- 225y- 125z = -915
-5z = -10

z= 2

now put z=2 in equation (3), we will get
32x +50y = 146
x = 146-50y …….. (a) ( continued)
32
put equation (a) in equation (1)

50x + 75y +40z = 305 ………….. (1)

50(146-50y ) + 75y +40(2) = 305
32
As z=2, put ‘z’ in above equation.
Solving the above equation we will get
y=1

put y=1 & z= 2 in equation (2)

30x + 45y+ 25z= 185 …………… (2)

30x + 45(1) + 25(2)= 185
30x = 185-95
30x= 90
x= 3

The company should fly:
3 Boeing 757
1 Boeing 767
2 Boeing 777

Q # 8

An item that cost Rs. 2300 was marked up 38 % of the selling price. After some time the item is markdown 30 %. Calculate the sale price after markdown.

SOLUTION:

Let selling price = 100
%Markup on selling price = 38%
Cost = 100-38 = 62
Thus Original Sale Price = (100/62) x 2,300
= Rs . 3,709.677

%Markdown = 30%
Rs. Markdown = 3709.677 x .30 = Rs. 1,112.903
Sale price after Markdown = 3,709.677 -1,112.903
= Rs. 2,596.774/-

sale price after markdown.= Rs. 2,596.774/-
salam! hi bro.u gave us no clue about how u done this question.ab ye lo mera solution which is 100% rite

Solution:

Let we assume:
Boeing 757 be ‘x’
Boeing 767 be ‘y’
Boeing 777 be ‘z’

x y z Total seats
Tourist 50 75 40 305
Economy class 30 45 25 185
First class 32 50 30 206

We have got three equations:

50x + 75y +40z = 305 ………….. (1)
30x + 45y+ 25z= 185 …………… (2)
32x+ 50y+ 30z = 206 …………… (3)

solving equation (1) & (2)

50x + 75y +40z = 305
30x + 45y+ 25z= 185
multiply equation (1) by 3, and equation (2) by -5, we will get:

150x+ 225y+ 120z = 915
-150x- 225y- 125z = -915
-5z = -10

z= 2

now put z=2 in equation (3), we will get
32x +50y = 146
x = 146-50y …….. (a) ( continued)
32
put equation (a) in equation (1)

50x + 75y +40z = 305 ………….. (1)

50(146-50y ) + 75y +40(2) = 305
32
As z=2, put ‘z’ in above equation.
Solving the above equation we will get
y=1

put y=1 & z= 2 in equation (2)

30x + 45y+ 25z= 185 …………… (2)

30x + 45(1) + 25(2)= 185
30x = 185-95
30x= 90
x= 3

The company should fly:
3 Boeing 757
1 Boeing 767
2 Boeing 777

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