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# MTH 302...Gdb no 4 .....(Start date : 1 august. 2016 ............End date : 10 august 2016)....Marks: 5

Question 1

Find the centered average and trends in the following data

 Quarter Actual Moving Average Centered Average Trend 1 157 2 87 3 184 184.5 4 310 186.5 5 165 183.5 6 75 192.5 7 220 206 8 364 212 9 189 209.5 10 65 205.75 11 205 192.25 12 310

Question 2

A club consists of 15 members. In how many ways can:

i)  the three officers: president, vice-president, and secretary-treasurer be chosen?

ii)  a committee of three members be selected?

Friends you can also see the gdb no 4 of MTH302  in Attachment

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### Replies to This Discussion

g iss wajah say 1st question ka table bilkul thek hai....

Ok thankyou

rahila plz second question mein  .......(ii) part ko achi tarikay say steps k saath solve kar day .....iss k baray mein confusion hai ....k yeh 455 kaisey aya hai ???

15C3 = 15! / 3! * (15-3)!

= 15! / 3!* (12)!

= 15.14.13.12 /3!*12!

=15.14.13 / 3.2.1

=2730/6

=455

thanku so much rahila...... 2730 aur 455 ...ways hain ya members hain  ya kuch aur ....yeh values kis ko represent kar rahi hain ???

rahila yeh 2nd question k 1st part ko full solve karey steps k saath .............15!/(15-3)!

15.14.13/?????........yeh nichey wala step kahan gya hai (15-3 ).....plz bataye ???

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MTH302 solution july 2016

Attachments:

Quarter Actual Moving Average Centered Average Trend
1 157
2 87
3 184 184.5 185.5 -1.5
4 310 186.5 185 125
5 165 183.5 188 -23
6 75 192.5 199.25 -124.25
7 220 206 209 11
8 364 212 210.75 153.25
9 189 209.5 207.625 -18.625
10 65 205.75 199 -134
11 205 192.25
12 310

In Centered Average: Add first and second Value of Moving Average and Divide by 2, same in next Column
Then in Trend: Subtract the Centered Average value from Actual value
Question 2
i) The order is important so use Permutation
15P3=2730
ii) The order is not important so use Combination
15C3=455

detail solution he post kr do question 1 aur 2 ke sath

Hello bro plz this two question is correct.

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