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In a hospital, births occur randomly at an average rate of 2 births per hour. Calculate the probability of observing
1. 3 births in a given hour at the hospital.
2. No birth in a given hour at the hospital."
Opening Date of Graded Discussion Board:
Friday, August 14, 2015 at 12:01 a.m.
Closing Date of Graded Discussion Board:
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Find the centered average and trends in the following data:
Quarter
Actual
Moving Average
Centered Average
Trends
1
143
2
56
3
164
141
4
208
138
1
132
137
2
52
140
3
176
138
4
198
137
1
126
135
2
44
132
3
164
129
4
188
Let X = No birth in a given hour at the hospital
Events occur randomly
Mean rate λ = 2 ⇒ X ∼ Po (2)
We want P(X ≥ 2) = P(X = 2) + P(X = 3) + ...
i.e. an infinite number of probabilities to calculate
but
P(X ≥ 2) = P(X = 2) + P(X = 3) + ...
= 1 − P(X < 2)
= 1 − (P(X = 0) + P(X = 1))
= 1 − (e−1.8 1.80 0! + e−1.8 1.81 1! )
= 1 − (0.16529 + 0.29753)
= 0.537
yeh theak ans kia
2.1 Examples
Births in a hospital occur randomly at an average rate of 1.8 births per hour.
What is the probability of observing 4 births in a given hour at the hospital?
Let X = No. of births in a given hour
(i) Events occur randomly
(ii) Mean rate λ = 1.8
⇒ X ∼ Po(1.8)
We can now use the formula to calculate the probability of observing exactly 4
births in a given hour
P(X = 4) = e−1.8 1.84
4!
= 0.0723
Please let me know the handout lecture or page no. just for the reference??
Dear, i have different answers how you're saying its 100 % correct?
Please share your comments OR solution if possible
Solution do bhay Sohail please
please tell me handout lecture or page no. just for the reference??
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