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In a hospital, births occur randomly at an average rate of 2 births per hour. Calculate the probability of observing

1.     3 births in a given hour at the hospital.

2.     No birth in a given hour at the hospital."

 

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Yar Sohail Bhayi please solution file he upload kr dein. ya phir handouts ka page no bta dein.

P(X=x)=

at page 279

μ=is an average rate of value.

x =is a poison random variable.

e =is the base of logarithm (e=2.718)

 

I):   3 births in a given hour at the hospital.

Poisson random variable (x) = 3

Poisson Probability: P(X = 3)

0.18045

 

II): No birth in a given hour at the hospital.

Poisson Probability: P(X = 0)

 

0.1353

μ=is an average rate of value.

x =is a poison random variable.

e =is the base of logarithm (e=2.718)

 

I):   3 births in a given hour at the hospital.

Poisson random variable (x) = 3

Poisson Probability: P(X = 3)

0.18045

 

II): No birth in a given hour at the hospital.

Poisson Probability: P(X = 0)

 

0.1353

100% correct

see handout page no. 280 for reference 

Please Discuss here about this GDB.Thanks
Our main purpose here discussion not just Solution
We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.

“In a hospital, births occur randomly at an average rate of 2 births per hour. Calculate the probability of observing

  1. 1.     3 births in a given hour at the hospital.
  2. 2.     No birth in a given hour at the hospital."

μ=is an average rate of value.

x =is a poison random variable.

e =is the base of logarithm (e=2.718)

 

I):   3 births in a given hour at the hospital.

Poisson random variable (x) = 3

Poisson Probability: P(X = 3)

0.18045

 

II): No birth in a given hour at the hospital.

Poisson Probability: P(X = 0)

 

0.1353

μ=is an average rate of value.

x =is a poison random variable.

e =is the base of logarithm (e=2.718)

 

I):   3 births in a given hour at the hospital.

Poisson random variable (x) = 3

Poisson Probability: P(X = 3)

0.18045

 

II): No birth in a given hour at the hospital.

Poisson Probability: P(X = 0)

 

0.1353

how u calculated ?????

3 births in a given hour at the hospital.

Poisson random variable (x) = 3

Poisson Probability: P(X = 3)

0.18045



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mth302 gdb 2 solution 2015

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