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Construct a real world business problem and then apply simple linear regression analysis.

 

 

tomorrow is last date..!! anybody share the solution

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Question:-

Suppose that 4 randomly chosen plots were treated with various level of fertilizer in the following yield of corn:-

Fertilizer(kg/Acre)

X

100

200

400

500

Production(Bushels/Acre)

Y

70

70

80

100

Estimate the Linear Regression of production Y on fertilizer X.

Solution:-

X

Y

XY

X2

100

70

7000

10000

200

70

14000

40000

400

80

32000

160000

500

100

5000

250000

å = 1200

å = 320

å =103000

å = 460000

Byx =  nåXY – åXåY / nåX2 - (åX) 2

Byx = 4(103000)-((1200)(320)) / 4(460000)-(1200) 2

Byx = 0.07

ayx = y - Byx X

= ((åY/n) – ((0.07) (åX/n))

=(320/4) – (0.07)(1200/4)

= 59

y = 59 + 0.07 X      is required regression equation.

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