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Aslamo Alaikum

Dear VU Fellowzzzzzzzzz

A topic related to the techniques of finding the particular integral for a non homogeneous differential equation is selected for graded discussion

Kindly share your ideas and discussions please for better GDB solution.

Thanks


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Please Discuss here about this GDB.Thanks

Our main purpose here discussion not just Solution

We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.

Consider the following methods of finding the particular integral for a non-homogeneous differential equation. Discuss the reasoning and answers of the given questions.

(a)    Methods of undetermined coefficient (Superposition approach and Annihilator approach)

(b)   Method of variation of parameters.

1) For which particular forms of the input function g(x), the methods of undetermined coefficients are used? Also, discuss the reason to restrict to those particular forms of g(x).

2) In what way do you think the method of variation of parameters has an advantage over the methods of undetermined coefficients.

what way do you think the method of variation of parameters has an advantage over the methods of undetermined coefficients  discuss PLZ

koi to idea da smjh ni a rahi 

koi to discuss kro, kal last date ha.

my all brothers and sisters thori thori mehnat karo sare t ho jay ga

Thori asan thori muskil .........

lec no. 17 book sa parho 

The input function can have one of the following forms: )(xg
‰ A constant function k.
‰ A polynomial function
‰ An exponential function e
x
‰ The trigonometric functions ) cos( ), sin( xxβ β
‰ Finite sums and products of these functions.
Otherwise, we cannot apply the method of undetermined coefficients

thankx for giving this info.

thanx 4 idea 

The input function gis restricted to have one of the above stated forms because of the
reason:
‰ The derivatives of sums and products of polynomials, exponentials etc are again
sums and products of similar kind of functions.
‰ The expression has to be identically equal to the input
function .
p
cy
p
by
p
ay ++/ //
)(xg
Therefore, to make an educated guess, is assured to have the same form as

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