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Discussion Topic:

Under what conditions the solution of the first order ordinary differential equation exist?

Furthermore, without solving the following initial value problem determine the interval in which the solution is certain to exist.

Opening Date: August 13, 2014 at 12:01 AM

Closing Date:  August 18, 2014 at 11:59  PM



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Replies to This Discussion


for question 2 .... see the link below.....


solve kuch bhi nhi karna... bus interval likhna hai  

what is the interval?


P(x) = tan(x)  that is continuous every where except (Pi/2 , 3Pi/2 , 5Pi/2 and so on )

Q(x) = sin(x)  that is continuous every where....

y=0 where x = Pi/4

so interval would be (-inf .+inf)

Question 1 me IVP and BVP ae ga..... mere Khayaal se.....

Q k 2nd part me IVP ka hi zikr hai saath

Abdul rauf bhai agr ap solution up load ker dey to every student submit. i think that ap ne solve ker leya hy. please brother time very short. 

bhai yar solution to kuch min k liye share kr do

please upload solution yarrrrrrrrr plz

Pls upload the solution in the students interest....

pls    pls      pls   /...........................

plzzzz 4rnd koi solution upload kar do pljjjjjjj koi idea 

Allah ka name le ker submit ker do jasa b kia hy.

lagta hae kisi nay kiya he nhiiiii


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