hmmm Aamir khan thnxx for shring ur idea
stay blessed
Please share of MTH401 of two question in one file..
plz help me kia mane q:2 thk kia ha ya galat
sadaf you solve it wrong
right to solve it is here
there is two part in question ----dx + ---dy=0
(1) (2)
differentiate first part w.r.t y ..............eq(1)
and second with respect to x ...............eq(2)
both will be equal
now integrate eq (2) w.r.t to y ..............eq(3)+ h(x)
compare it with eq (1)
you will find the missing term h(x)
integrate h(x) w.r.t x and put it value in eq(3)
then the answer is ready
ATTENTION here i m a little wrong correct way is that
right to solve it is here
there is two part in question ----dx + ---dy=0
(1) (2)
differentiate first part w.r.t y ............(M)
and second with respect to x ............(Y)
both will be equal
now integrate part 2 w.r.t to y
then differentiate it w.r.t x .........eq(3)+h(x)
compare it with M
you will find the missing term h(x)
integrate h(x) w.r.t x and put it value in eq(3)
then the answer is ready
thanku so much
thanku so much
mujhy 1st question ka b bta den plz
yeh wrong answer hai ap ka sadaf awan
Koi tou Allah ka banda Rehm kary or Assignment solve krny me guide kr dy
2nd question answer is right or wrong please reply
y2sinx-x3y-x2=1/e
© 2022 Created by + M.Tariq Malik. Powered by
Promote Us | Report an Issue | Privacy Policy | Terms of Service
We are user-generated contents & non-commercial site since 2009. All product, videos, pictures & others contents on site don't seem to be beneath our Copyrights & belong to their respected owners & freely available on public domains. All Contents on site are for personal & non-commercial use.We believe in Our Policy & do according to them. If Any content is offensive in your Copyrights then please email at m.tariqmalik@gmail.com with copyright detail & We will happy to remove it immediately.
Management: Admins ::: Moderators
Awards Badges List | Moderators Group
All Members | Featured Members | Top Reputation Members | Angels Members | Intellectual Members | Criteria for Selection
Become a Team Member | Safety Guidelines for New | Site FAQ & Rules | Safety Matters | Online Safety | Rules For Blog Post