We are here with you hands in hands to facilitate your learning & don't appreciate the idea of copying or replicating solutions. Read More>>
+ Link For Assignments, GDBs & Online Quizzes Solution |
+ Link For Past Papers, Solved MCQs, Short Notes & More |
Dear Students! Share your Assignments / GDBs / Quizzes files as you receive in your LMS, So it can be discussed/solved timely. Add Discussion
How to Add New Discussion in Study Group ? Step By Step Guide Click Here.
Tags:
+ How to Follow the New Added Discussions at Your Mail Address?
+ How to Join Subject Study Groups & Get Helping Material? + How to become Top Reputation, Angels, Intellectual, Featured Members & Moderators? + VU Students Reserves The Right to Delete Your Profile, If?.
+ http://bit.ly/vucodes (Link for Assignments, GDBs & Online Quizzes Solution)+ http://bit.ly/papersvu (Link for Past Papers, Solved MCQs, Short Notes & More)
+ Click Here to Search (Looking For something at vustudents.ning.com?) + Click Here To Join (Our facebook study Group)welcome bro... :)
please Evergreen post complete solution of gbd I am so confused
Allah gives u long live
LINEAR ALGEBRA MTH_501
GDB
Question 1:
Standard basis vectors for are and. If we want to insert into this Basis, then which vector from Standard basis can be removed while still maintaining the Basis of.
Discuss the cases when:
(i) =
(ii) =
Interpret the result geometrically in both cases.
Solution:
(i) will maintain basis of on removal of any of vector from standard basis as each set will form independent set.
Remove v1
Using echelon form
Hence u=0, y=0, z=0 therefore set is independent
Linearly independent as (4, 3, 6) does not lies b\w (0, 0, 1) and (0, 1, 0)
Remove v2
x+4u=0, u=0, z=0 therefore x=0, u=0, z=0. Set is independent
Linearly independent as (4, 3, 6) does not lies b\w (1, 0, 0) and (0, 0, 1)
Remove v3
x+4u=0, y+3u=0, u=0 therefore x=0, y=0, u=0. Set is independent
Linearly independent as (4, 3, 6) does not lies b\w (1, 0, 0) and (0, 1, 0)
(ii) will maintain basis of only on removal of and vector from standard basis, but vector will not maintain basis of .On the removal of vector will form dependent set.
Remove v1
Using echelon form
Hence u=0, y=0, z=0 therefore set is independent
Linearly independent as (4, 0, 6) does not lies b\w (0, 0, 1) and (0, 1, 0)
Remove v3
x+4u=0, 6u+z=0, x=2/3z, u=x/-4, z=3/2x. Set is dependent
Linearly dependent as (4, 0, 6) lies b\w (1, 0, 0) and (0, 0, 1)
Remove v3
x+4u=0, y=0, u=0 therefore x=0, y=0, u=0. Set is independent
Linearly independent as (4, 0, 6) does not lies b\w (1, 0, 0) and (0, 1, 0)
Very Nice.. Gud Effort..its 100% correct solution.
apka solution kaafi helpful or exact hai but apny late upload kya tha so i couldn't gain any benefit from it... :(
Good Luck!!
malika api, is it correct or the upper solution is correct? plz hurry
kindly ab jald az jald isay complete kr lein..
Best of Luck to all of U..!
I think babr ka sahi he
ye solution ha
© 2020 Created by + M.Tariq Malik. Powered by
Promote Us | Report an Issue | Privacy Policy | Terms of Service
VU Students reserves the right to delete profile, which does not show any Activity at site nor has not activity more than 01 month.
We are user-generated contents site. All product, videos, pictures & others contents on vustudents.ning.com don't seem to be beneath our Copyrights & belong to their respected owners & freely available on public domains. We believe in Our Policy & do according to them. If Any content is offensive in your Copyrights then please email at m.tariqmalik@gmail.com or Contact us at contact Page with copyright detail & We will happy to remove it immediately.
Management: Admins ::: Moderators
Awards Badges List | Moderators Group
All Members | Featured Members | Top Reputation Members | Angels Members | Intellectual Members | Criteria for Selection
Become a Team Member | Safety Guidelines for New | Site FAQ & Rules | Safety Matters | Online Safety | Rules For Blog Post