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Disscuss MTH603 Assignment no 2 due date is 14 July 2014
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MTH603 - Numerical Analysis Assignment No. 2 Solution and Discussion Spring 2014 of VirtualUniversity (VU) Due Date: July 14, 2014
Assignment # 2 (Lecture# 23 - 28) Of MTH603 (Spring 2014)
Maximum Marks: 30
Due Date: 14 July, 2014
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Question: 1 Marks: 5 + 10
Using Lagrange’s interpolation formula, find the value of cos
6
π
using the following table.
Also
estimate the error in the solution.
x 0
4
π
2
π
y x =cos 1 0.7071 0
Question: 2 Marks: 2.5 + 2.5 + 5 + 5
Estimate (2 3. ) d
dx
and (1 3. ) d
dx
, using the following table.
x 1.3 1.5 1.7 1.9 2.1 2.3
y 3.753 3.523 3.333 1.9922 1.5442 1.2969
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check this if error then accurate this
SINCE X=2.3 OCCURS AT THE END OF THE TABLE,SO WE WILL USE BACKWARD DIFFERENCE FORMULA for derivatives
The backward difference table for the given data is given below
X |
F(x) |
Δy |
y |
y |
y |
y |
1.3 |
3.753 |
|
|
|
|
|
1.5 |
3.523 |
-0.5 |
|
|
|
|
1.7 |
3.333 |
-0.1900 |
0.3100 |
|
|
|
1.9 |
1.9922 |
-1.3400 |
-1.1500 |
-1.4600 |
|
|
2.1 |
1.5442 |
-0.4480 |
0.8920 |
2.0420 |
3.5020 |
|
2.3 |
1.2964 |
-0.2773 |
0.1707 |
-0.7213 |
-2.7633 |
-6.2653 |
NOW FOR
SINCE 1.3 appear at the beginning of the table so we will use forward difference formula for which table is given below
X |
F(x) |
Δf(x) |
f(x) |
f(x) |
f(x) |
f(x) |
1.3 |
3.753 |
|
|
|
|
|
1.5 |
3.523 |
-0.5 |
|
|
|
|
1.7 |
3.333 |
-0.1900 |
0.3100 |
|
|
|
1.9 |
1.9922 |
-1.3400 |
-1.1500 |
-1.4600 |
|
|
2.1 |
1.5442 |
-0.4480 |
0.8920 |
2.0420 |
3.5020 |
|
2.3 |
1.2964 |
-0.2773 |
0.1707 |
-0.7213 |
-2.7633 |
-6.2653 |
Using the forward difference formula
=
=
==-5.8270
is ka table ghalat hai...........
g 0.04 ki jaga 0.4 likha hua hy
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