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# MTH603 Numerical Analysis Friday, November 13, 2015 to Monday, November 16, 2015 GDB

Solve the equations x3 – 3x+ 0 in the interval [0,1] using the Regula Falsi Method(Method of False Position) up to two iterations.

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### Replies to This Discussion

Guys share your current GDB solution discuss them help each other

f(x)=x^3 - 3x + 1=0
taking first edge value
f(0) = (0)^3 -3(0)+1=0
f(0)=1
and second edge
f(1)= (1)^3 - 3(1)+1=0
f(1)= -1
these have opposite sign so root lies between x1= 1 and x2= -1
x3 = x2 - {(x2-x1)/f(x2)-f(x1)f(x2)}
x3=1-(1-0)/(-1-1)(-1)= 1-( 1/-2)(-1)= 1 - (- 1/-2)
= 1 - 1/2 = 0.5
f(x3)= (0.5)^3 - 3(0.5)+1=0.125 - 1.5 +1 = -0.375
koi friend bta sakta hai aisy hoga solution plz es ko chek krna because mein biology wala hoon math ni parhi howi plz

same mera b bio h subjct ab iski detail smh n a ri.......... sum1 plz hlp.........

yes it is correct!

now f(x1) and f(x3) have opposite signs, root lies b/w x1 = 0 and x3 = -0.375

x4 = x3 - (x3-x1)/f(x3)-f(x1)*f(x1)

after calculating the value of x4, find out f(x4).

yar ya pata kasay lagay ga kay kis kay opposite  sign dakhnay han oor kaha pr hum ans khtem krna ha.

Zubair you have committed a mistake, in 9th line, root lies b/w x1 = 0 and x2 = 1.

becoz 1 and -1 are values of f(x1) and f(x2).

Our main purpose here discussion not just Solution

We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.

Please share solution and discuss with each other best solution will be come.

Hira thanks alot  sai ans kia ha ?

Guys share your current GDB solution discuss plz

guyx could u plz tell me what is the mean of (up to two iterations) im confused in it ...... we solve it till f(x4) or we have to solve it further f(x5) or f(x6)

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