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PHY101 1st assignment fall 2012. due date 19-11-2012 plzz discuss here in one blog

Physics (PHY101) VU of Pakistan
Assignment 1: (Fall 2012)
PHYSICS (PHY101)
TOTAL MARKS: 25
Due Date: 19/11/2012
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Don’t wait for the last date to submit your assignment.
Question # 1
A football player kicks a football straight up in to the air with an initial velocity of 25m/s. What
is the approximate maximum height that the ball reaches? Use acceleration due to gravity (g) as
9.8m/s2. Marks = 7
Question # 2
Physics (PHY101) VU of Pakistan
In the classic horse and cart problem, a horse is attached to a cart that can roll along on a set of
wheels. Which of the following statement is true? Also explain the reason of your selected
choice as well.
a) The horse pulls on the cart with a force, and the cart pulls, back on the horse with an
equal force.
b) The horse pulls on the cart with a force greater than the force that the cart pulls back on
the horse.
c) The horse pulls the cart forward because the force of friction forward is greater than the
force of the wagon backward.
d) The horse pulls the cart forward, because of a time delay between the action and reaction
forces.
e) The horse pulls the cart forward, but only if the horse has a mass greater than the mass of
the cart. Marks = 6 (2+4)
Question # 3
Is it true to say that a projectile has zero acceleration at its peak? If yes explain if not give a
reason. Marks = 4
Question # 4
(a)Anna is pushing but the box does not move. What is the force of static friction shown in
below figure? Marks = 3
(b) What is the maximum static friction force shown in below figure? The coefficient of static
friction for these materials is 0.31. Marks = 5
Physics (PHY101) VU of Pakistan
<Wish you good luck>>>>>>>>>>>>

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plz discuss here

for 1st question we use formula 2as=vf^2-vi^2

here we take a=g,nd vf=0

koi to idea solution share kare dy.... 

Please Discuss here about this assignment.Thanks

Our main purpose here discussion not just Solution

question  no 1 ka answer hai 

 

h= - 1.27

you use 2as=vf^2-vi^2 equation to find distance????

Asslamu-a-laikum!

                          please anybody share there ideas about this assignment.

guys vi^2 = 25^2 or vi^2= 25

arent we calculate the square or do we hv to? lemme knw plz

if we including the sqaure thn answer is coming in -31.7 and if we not taking square then answer is -1.27 :O :/

PHY101 Assignment Solution: 1
Q 1: A football player kicks a football straight up in to the air with an initial velocity of 25m/s. What is the approximate maximum height that the ball reaches? Use acceleration due to gravity (g) as 9.8m/s2. Marks = 7

Ans:-
2as = Vf2 – Vi2
Where a = g = 9.8m/s2
Vf2 = 0
Applying the values:
2as = Vf2 – Vi2
2(9.8m/s2) s = 0 – (25m/s)2
(19.6m/s2) s = 625m2/s2
s =625m2/s2 / (19.6m/s2)
s = 31.8m


Q 2: In the classic horse and cart problem, a horse is attached to a cart that can roll along on a set of wheels. Which of the following statement is true? Also explain the reason of your selected choice as well.
a) The horse pulls on the cart with a force, and the cart pulls, back on the horse with an equal force.
b) The horse pulls on the cart with a force greater than the force that the cart pulls back on the horse.
c) The horse pulls the cart forward because the force of friction forward is greater than the force of the wagon backward.
d) The horse pulls the cart forward, because of a time delay between the action and reaction forces.
e) The horse pulls the cart forward, but only if the horse has a mass greater than the mass of the cart. Marks = 6 (2+4)

Ans:-
c) The horse pulls the cart forward because the force of friction forward is greater than the force of the wagon backward.

Reason:-
The forces on the cart include the forward force the horse exerts on the cart and the backward force due to friction at the ground, acting on the wheels. At rest, or at constant velocity, these two are equal in size, because the acceleration of the cart is zero. The forces on the horse include the backward force the cart exerts on the horse and the forward force of the ground on its hooves. At rest, or at constant velocity, these two are equal in size, because the acceleration of the horse is zero. The force the horse exerts on the cart is of equal size and opposite direction to the force the cart exerts on the horse, by Newton's third law. The horse places its feet so as to change the angle of the force its hooves exert on the ground, thereby increasing the backward force of its hooves on the ground.

Q 3: Is it true to say that a projectile has zero acceleration at its peak? If yes explain if not give a reason. Marks = 4

Ans:-
The acceleration due to gravity is constant at 9.8 m/sec^2. One of the variables in projectiles is its speed --- it slows down as it goes up and gains speed as it goes down. When the projectile reaches its maximum height, its velocity is always zero. Acceleration has nothing to do with instantaneous velocity. Acceleration shows the relationship between the velocities of the projectile at 2 different points in time. If acceleration was zero, the difference in velocity of the projectiles between any two points of its trajectory would be 0. However, with an acceleration, even if the velocity of the projectile at one point was 0, but the acceleration would not be zero because the acceleration of a projectile is always equal to the acceleration of gravity.



Q 4: (a) Anna is pushing but the box does not move. What is the force of static friction shown in below figure? Marks = 3

Ans:-
Fs=mu*N
=1*7N
=7N

(b) What is the maximum static friction force shown in below figure? The coefficient of static friction for these materials is 0.31. Marks = 5

Ans:-

F s max= mu s * N
=0.31*27N
=8.37N

Thank you very much for sharing your idea.

Naila Awan gud keep it up & thanks 

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