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PHY101 2st assignment fall 2012. due date 04-12-2012 plzz discuss here..

PHY101 2st assignment fall 2012. due date 04-12-2012 plzz discuss here..

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Please someone discuss this assignment also.

Please Discuss here about this assignment.Thanks

Our main purpose here discussion not just Solution

Question # 4

If an object on a horizontal, frictionless surface is attached to a spring, displaced, and then

released, it will oscillate. If it is displaced 0.120 m from its equilibrium position and released

with zero initial speed, then after 0.800 s its displacement is found to be 0.120 m on the opposite

side, and it has passed the equilibrium position once during this interval.

Find (a) the amplitude; (b) the period; (c) the frequency.


Answer of Q-4

a)When object moved 0.120m from its equilibrium position say to the right. Then after 0.800 sec it has passed through its equilibrium position and reached to the opposite side at 0.120 m from equilibrium. Then it has covered 0.240 m to reach to the other end.(0.120+0.120)

therefore amplitude is 0.240.. 

b) Period:To complete half cycle the time taken is 0.800 sec. To complete one cycle it will take 1.6 sec.

Period is the time to complete one cycle. Here Period is 1.6 sec.

c)Frequency:frequency=1/T where T is the period or time period.

Therefore Frequency=1/1.6 cycles/sec. Here we must denote it in hertz. so frquecy is 1/1.6 hertz

Q-3 A person takes a 2.0Kg mass and lifts it 0.50m above a table that is itself 1.0m above the floor.

The person then moves the mass 1.0m to the side so that it is directly over the floor, 1.50m

below. Which statement is true?

a) The mass has 30.0J of Gravitational Potential Energy (GPE) relative to the floor.

b) The person did 10.0J of work in lifting the mass.

c) The mass has 10.0J of Gravitational Potential Energy (GPE) relative to the table.

d) The person did not work against gravity when moving the mass 1.0m to the side.

e) All of the above are true.

Anawer is e

Reason:

a) Energy relative to Floor =PE=mgh=2x9.8x1.5=30Joule(consider 9.8=10)

b)Person work done against the gravity in lifting=PE=mgh=2x10xx0.5)=10Joule (g=10m/s^2)

c)Energy possess relative to table =PE=mgh=2x10x0.5=10Joule

d)In physics he did not any waork against gravity while moving to side.

e) All of above is correct answer

 

 

please anybody tell me what is light wave speed formula

Anybody please discuss all the questions. And please share some past mid-term papers.

phy101 solved midterm paper

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Thank you very much. I will pray that all VU students score high marks in there exams.

Please anyone Share there ideas about Questions of 2nd assignment.

i have uploaded phy101-2 solution for all.

thanx

jis ko solution chahiya apna email id yahan par add kar da main yahan par send nae kar sakta beacuse plagiarism ka prob ha ha.. 

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