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PHY101 2st assignment fall 2012. due date 04-12-2012 plzz discuss here..

PHY101 2st assignment fall 2012. due date 04-12-2012 plzz discuss here..

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Assignment 2: (Fall 2012)

PHYSICS (PHY101)

 

Question # 1

In one experiment, a red wagon at rest is pushed to the left with a force of 150N for 1.0s. In a second experiment a blue wagon with the same mass as the red wagon is pushed from rest to the left with a force of 150N for 2.0s. Which statement below is true?

 

a) The red wagon had a smaller impulse but a larger change in momentum than the blue.

b) The red wagon had a smaller impulse and a smaller change in momentum than the blue.

c) The red wagon had a same impulse and a same change in momentum as the blue.

d) The red wagon had a larger impulse but a smaller change in momentum than the blue.

e) The red wagon had the same impulse but a larger change in momentum than the blue.

*Write the reason of your above selected choice as well.

Reason:-

The red wagon had a smaller impulse because the red wagon is pushed for 1 sec as compared to blue. The value of force is same the time limit is short in this experiment. Same is the case for change in momentum. It is facing force for short time interval as compared to the red wagon so its momentum is smaller.

Question # 2

The light’s wavelength is 6.0×10-7 m. The light completes 5.0 cycles in 10-14 seconds. What is the light’s wave speed? Marks = 5

Wave speed = frequency x wavelength.

Wavelength = 6.0×10-7 m

Frequency = 5.0/10-14

                      = 5.0*1014

Now

Wave speed = 6.0×10-7×5.0×1014

                        = 30.0 × 107m.

 

Question # 3

A person takes a 2.0Kg mass and lifts it 0.50m above a table that is itself 1.0m above the floor.

The person then moves the mass 1.0m to the side so that it is directly over the floor, 1.50m below. Which statement is true?

 

a) The mass has 30.0J of Gravitational Potential Energy (GPE) relative to the floor.

Answer;-

PE=mgh

                            = 2.0×1.5×10=30.0 J correct option.

b) The person did 10.0J of work in lifting the mass.

Answer:-

                        PE=mgh

                            =2.0×0.5×10=10.0 J correct option.

c) The mass has 10.0J of Gravitational Potential Energy (GPE) relative to the table.

Answer:-

                        PE= mgh

                            = 2.0×0.5×10=10.0 J correct option.

d) The person did not work against gravity when moving the mass 1.0m to the side.

Answer:-

Value of gravity is constant horizontally so work done horizontally at a fixed height is constant anywhere.

e) All of the above are true.

 

*Write the reason of your above selected choice as well.

 

Question # 4

If an object on a horizontal, frictionless surface is attached to a spring, displaced, and then released, it will oscillate. If it is displaced 0.120 m from its equilibrium position and released with zero initial speed, then after 0.800 s its displacement is found to be 0.120 m on the opposite side, and it has passed the equilibrium position once during this interval.

Find

(a) The amplitude;

Answer:-

=0.12m+0.12m

=0.24m

 (c) The frequency.

F=1/T

  = 1/0.8

  = 1.25 s-1

 

(b) The period;

T=1/f

  = 1/1.25

  = 0.8 sec.

Phy101_2nd Assignment Solution

See the attached file please

Attachments:

PHY101_Current_Assignment_No.2_Solution_Idea_Fall_2012

Attachments:

plz koi mujhe first question samjhaye ga?

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