We have been working very hard since 2009 to facilitate in your learning Read More. We can't keep up without your support. Donate Now.

www.bit.ly/vucodes

+ Link For Assignments, GDBs & Online Quizzes Solution

www.bit.ly/papersvu

+ Link For Past Papers, Solved MCQs, Short Notes & More


+ http://bit.ly/vucodes (Link for Assignments, GDBs & Online Quizzes Solution)

+ http://bit.ly/papersvu (Link for Past Papers, Solved MCQs, Short Notes & More)

+ Click Here to Search (Looking For something at vustudents.ning.com?)

+ Click Here To Join (Our facebook study Group)


Views: 1543

Replies to This Discussion

and 1st question part 2???

Q1 PART 2

Attachments:

Q2 IS SOO EASY DO IT BY YOURSELF.

Q3.I THINK THE FORMULA USED IN Q3 IS F=ILB .I IS CURRENT L IS LENGTH OF WIRE AND B IS MAGNETIC FIELD. ALL THE VALUES IS GIVEN JUST PUT IN FORMULA

Adnan Bro Q.1 ka complete part share kren>>>

when you get f from part (a) then put it in this formula 

a= f/m     m is the mass of proton = 1.67*10^-27

for example a = 8.67*10^-13/ 1.67*10^-27=your answer 

f=2.30544*10^-13

a=1.380*10^-40

kia yeh 1 que k answers theek h koi bta de plz

mje ye ghalat lg raha hai... F= 0.867*10^-13 ata hai i think

u r right

or sin@ ka kia kerna ? F=IBLsin@ ye formula hai na. (i mean tita by @ )

Q1 PART A

Attachments:



RSS

Looking For Something? Search Here

HELP SUPPORT

This is a member-supported website. Your contribution is greatly appreciated!

© 2020   Created by +M.Tariq Malik.   Powered by

Promote Us  |  Report an Issue  |  Privacy Policy  |  Terms of Service

.