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mujhe question no. 1 ki samjh nai aai hai.

Q= m (Lf + cicc      delta Ticc       + c water   delta T water    )


is may mujhe value add kr k do plz chowder




       Q=1.80(Lf =3.34*105J/kg+cice = 2100J/kg.K   deltaTice      cwater =4190J/kg.K  delta T water)


plz help me in question no. 1 according to assignment.

mujhe samajh nai aai hai. value put kr k batayon? 


As length=2cm=.02m

So volume =l*l*l=l^3

Vol =(.02)3=.0008m^3

T1=20C and T2=90C



Given that  p=1.01*10^5 Pa

(a)    increase in volume of cube=?

As V2 –V1= B(T2-T1)

V2-V1=5.1*10^-3 *.0008 *343

Increase in volume =133994.4*10^-7 m3

(b)   work done=?



W=1.01*10^5 *133994.4 * 10^-7

W=14134.344 *10^-2


(c)    heat added=?

At constant pressure,Cp=Qp/deltaT

Qp=Cp *delta T

Qp=390 *343

=133770 J

(d)   as Q=delta U +W



=133628.637 J


masoor sb please help me in question no. 1



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