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# Solution PHY101 6th assignment CHowder

hello its a little help from me to phy101 students ..

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mujhe question no. 1 ki samjh nai aai hai.

Q= m (Lf + cicc      delta Ticc       + c water   delta T water    )

is may mujhe value add kr k do plz chowder

Q=1.80(Lf =3.34*105J/kg+cice = 2100J/kg.K   deltaTice      cwater =4190J/kg.K  delta T water)

plz help me in question no. 1 according to assignment.

mujhe samajh nai aai hai. value put kr k batayon?

Q#2:

As length=2cm=.02m

So volume =l*l*l=l^3

Vol =(.02)3=.0008m^3

T1=20C and T2=90C

T2-T1=90-20=70C

T2-T1=70+273=343K

Given that  p=1.01*10^5 Pa

(a)    increase in volume of cube=?

As V2 –V1= B(T2-T1)

V2-V1=5.1*10^-3 *.0008 *343

Increase in volume =133994.4*10^-7 m3

(b)   work done=?

W=P*deltaV

W=P(V2-V1)

W=1.01*10^5 *133994.4 * 10^-7

W=14134.344 *10^-2

W=141.34J

At constant pressure,Cp=Qp/deltaT

Qp=Cp *delta T

Qp=390 *343

=133770 J

(d)   as Q=delta U +W

deltaU=Q-W

=133770-141.343

=133628.637 J

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