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# Assignment 3(Spring 2013)

Circuit Theory (Phy301)

Marks: 30

Due Date: June 27, 2013

DON’T MISS THESE Important instructions:

• To solve this assignment, you should have good command over first 28 lectures.
• Upload assignments properly through LMS, (No Assignment will be accepted through email).
•  Write your ID on the top of your solution file.
• All students are directed to use the font and style of text as is used in this document.
• Don’t use colorful back grounds in your solution files.
• Use Math Type or Equation Editor etc for mathematical symbols.
• This is not a group assignment, it is an individual assignment so be careful and avoid copying others’ work. If some assignment is found to be copy of some other, both will be awarded zero marks. It also suggests you to keep your assignment safe from others. No excuse will be accepted by anyone if found to be copying or letting others copy.
• Don’t wait for the last date to submit your assignment.
• You can draw circuit diagrams in “Paint” or in “Corel Draw”. The simple and easy way is to copy the given image in Paint and do the required changes in it.

Q 1:

Find the voltage V0 of the given network, by using source transformation method. Write each step of calculation. Draw the circuit diagram where necessary and mention the units of calculated values.

Q 2:

Find the voltage V0 of the given network, by using super position method method. Write each step of calculation. Draw the circuit diagram where necessary and mention the units of calculated values.

Q 3:

Find the current IX flowing through 6Ω of the given network, by using Norton theorem. Write each step of calculation. Draw the circuit diagram where necessary and mention the units of calculated values.

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Attachments:

### Replies to This Discussion

koi btaye ga k file attach kaisy hogi :(

mera 1st ka 1.6 aa rha hai

Koi 3rd ka batye ga

Mera bhi 1st ka 1.6 aa raha hai

3rd question ka solution dy do na koi plzzzzzzzzzzzzzzzzzzzz

APP r1 ko 1K or R2 ko 3K rako phir app ka answer 4.5 aye ga jo correct hai :D

NHI correct ji

jub hum 6 v and 3 k ko conert krty hain tow 3 k dobara parallel ho jata hai

wo 3k nahe ata Ohms law say 2mAcurrent find hota hai jo 4V k parallel ho hai jis say Phr ohms law say resistance find ho jati hai jo 1K resistance ata hai jis ko hum R1 kehaty hain or dosri 3K resistance hoti hai jis k hum R2 kehtay hain or 18 V voltage hota hai or Phir Vo ka forumla lag k 4.5 V aanswer ata hai

Kya faida huwa yaha discussion karnay ka kisi nay discuss he nahe kiye solution

hahahah yr 3rd ka kuch bta do plz

3rd question kisi ko nahe ata

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