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Hey guyz i am having problem with the second question of Assignment No. 6......need some help!!!!

 

Q.2

Find the waveform of output voltage V0 for the following clipper circuit with given         signal waveform at input               



 

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Assignment 6 (Spring 2011)    

 

                            

Q.1

 Determine the dc load voltage and turn ratio for the circuit shown below.

 

 

 

 

 

 

 

 

 

 

 

 

 

Solution

 

SOLUTION:

Primary voltage is in rms so we can calculate the peak voltage

                                                             V1 (pk) = Vrms/0.707

                                                                                    = 60/0.707

                                                                          = 84.86Vpk

Primary voltage and turn ratio is known so we can determine the secondary voltage

                                       V2 (pk) = (N2/N1) V1pk

                  P;liputting the values we have,

                                                            =33.94Vpk

Now load voltage can be calculated as

                                        VL (pk) = V2/2 – 0.7

                        putting the values we have,

                                                = 33.94 /2 – 0.7                      

                                                 = 16.27Vpk

Now dc value of the voltage can be calculated as

                                                Vave = 2VL (pk)/ Π

      putting the values we have,

                                                          = 2*16.27/ Π

                                                         

                                                         = 10.34 Vdc ______________Answer.

Turn ratio is 

                              N2/N1=2/5    =  0.4

Q.2

Find the waveform of output voltage V0 for the following clipper circuit with given         signal waveform at input               

 

 

 

 

 

 

Solution:-

 For diodes are ideal than,

                        When voltage reaches to 5 voltage the diode D1 will conduct and diode D2 will not conduct. And also when voltage ranges to negative 3.0 voltages the diode D2 will conduct and D1 will not conduct.

Therefore positive voltage above +5 voltage and negative voltages below – 3.0 are clipped off and the resulting waveform will be as shown below.

 

 

 

 

 

 

Thank you very much dastgeer sab but 1st question d calculations ghalat ne tadyan

 

PHY 301 Assignment No.6 Solution 

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