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STA100 GDB Fall 2020 Solution / Discussion

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STA 100 GDB 1 solution Fall 2020 || solution GDB STA100 solution fall 2020 virtual university vu

STA100 Solution GDB Fall 2020

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STA100_GDB_Solution_Fall_2020

STA100 GDB Solution Fall 2020 Complete Correct Solved

STA100 GDB 1 Idea Sol Fall 2020 File 

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STA100 GDB 1 Idea Sol Fall 2020

STA100 General Mathematics and Biostatistics GDB 1 Solution & Discussion Fall 2020


Question Description

Dear Students,

 

Solve the Quadratic Equation

{x^2} - 18x + 45 = 0  by factorization method.

STA100 General Mathematics and Biostatistics GDB 1 Solution & Discussion Fall 2020


STA100 GDB Solution.

 

{x^2} - 18x + 45 = 0

{x^2} - 15x - 3x + 45 = 0

x\left( {x - 15} \right) - 3\left( {x - 15} \right) = 0

\left( {x - 15} \right)\left( {x - 3} \right) = 0

\begin{array}{l} Now\\ x - 15 = 0\;\;\;\;\;\;\;,\;\;\;\;\;\;\;\;\;x - 3 = 0 \end{array}

\begin{array}{l} \;\;\;\;\;\;x = 15\;\;\;\;\;\;,\;\;\;\;\;\;\;\;\;\;\;\;\;x = 3\\ \;\;\;\;\;\;\;\;\;\;\;\;Solution\;Set = \left\{ {15,3} \right\} \end{array}

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