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Assignment no.1 (Lessons 1 – 15)

 

Question 1:                                                                                                                Marks: 3+2=5

a)      The mean age of a group of 100 persons was found to be 32.02. Later it was discovered that age 57 was misread as 27. Find the corrected mean?

 

b)      The sum of deviations from an arbitrary value A = 15 for 10 values is 25, find the A.M.

 Question 2:                                                                                                               Marks: 3+3=6

a)      The mean of 200 items is 48 and their S.D is 3. Find the values of  and  

 

b)      A vehicle going up from Islamabad to Murree consumes petrol at the rate of One liter per 8 km, while going down from Murree to Islamabad one liter per 12 km. Find the average rate of consumption between the two cities.                                                                                                          

 

Question 3:                                                                                                                         Marks: 4

The S.D of the symmetrical distribution is 5. What must be the value of, and also explain that the distribution will be?                                                                                                                                   

(i)                 Meso-kurtic

(ii)               Platy-Kurtic

(iii)             Leptokurtic


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#STA301 #FST #QUESTION ANSWER

Xmean = (1/100)*∑xi

∑xi = 32.02*100 = 3202

New Xmean is

∑xi = 3202 - 27 + 57 = 3232

Correct Xmean = 3232/100 = 32.32, (c)

Q2(A) HINT 

‪#‎STA301‬ Q3 ‪#‎Solution‬
Q3#The S.D of the symmetrical distribution is 5. What must be the value M4 of , and also explain that the distribution will be? 
(i) Meso-kurtic
(ii) Platy-Kurtic
(iii) Leptokurtic

Thank you !

Is it right?????

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