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Assignment No.1 (Course STA301) before or on 01-06-2015, (23:59)P.M

Assignment no.1(Lessons 1 – 11)

Question 1:                                                                                                  Marks: 2+5=7

a)      In a moderately skewed distribution mean = 60 and median = 55. Find Mode?

b)  Arrange the data given below in an array and construct a frequency distribution using a class interval of 5. Calculate the class- limits and class-boundaries and the starting value is 55.0

79.4, 71.6 ,  95.5, 73.0, 74.2, 81.8, 90.6, 55.9, 75.2, 81.9, 68.9, 74.2, 80.7, 65.7, 67.6, 82.9, 88.1, 77.8, 69.4, 83.2, 82.7, 73.8, 64.2, 63.9, 58.3, 83.5, 70.8, 72.1, 71.6, 59.4, 77.6.

Question 2:                                                                                         Marks:2+6=8

a)      For a set on n values of  , it is known that  , , find ?

b)     The following are the scores made by two batsmen A and B in series of innings:

A:        28        22        46        85        9          59        175      42        11        92

B:        52        18        4          95        125      12        90        58        7          76

i)                    Who is better as a run getter?

ii)                  Who is more consistent player?

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A)    In a moderately skewed distribution mean = 60 and median= 55. Find Mode?

Mode = 3median-2mean

=3(55)  - 2(60)

= 165 – 120

Mode=  45

Moderately skewed distribution  k liye yehi formula lagye ga na ???

yeshhh sisooo

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