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### Replies to This Discussion

Our main purpose here discussion not just Solution

We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.

71.95+3/17(36/2-10)

=73.36

kon sa formula use kia

To find the median of a frequency distribution we use the following formula:

X= l + h/f(n/2-c)

Where:

l =lower class boundary of the median class="71".95.

h=class interval size of the median class="3"

f =frequency of the median class="17"

n=total no. of observations=36

c =cumulative frequency of the class preceding the median class="10"

putting all these values in the formula:

X=l + h/f(n/2-c)

x=71.95+3/17(36/2-10)

x=71.95+3/17(18-10)
x=71.95+3/17(8)
x=71.95+0.176(8)
x=71.95+1.412
x=73.36.

x=l+h/f(n/2-c)

x=71.95+3/17(36/2-10)

x=71.95+3/17(18-10)

x=71.95+3/17(8)

x=71.95+36/17

x=1223.15+36/17

x=1259.15/17

x= 74.067 Ans

muje yeh btaen google se kese math k qu

X= l+h /f (n/2-c)

X=71.95+3/17(18 -10)

X= 71.95+ 0.176(8)

X=71.95+1.411

X=73.36

Salam Tariq bhai ye steps kaisay solve kiyin hain?

x=71.95+3/17(8)
x=71.95+36/17

x=1223.15+36/17

Mera jawab

~X = 71.95 + 0.17(8)

~X = 71.95 + 1.36

~X = 73.31

arha hae

bhai jan 36 kaise aata hai .  8 x 3 = 24 ...!!

kya hm is trhn solve kar skty hain ya equation bna k hi solve karna hai

Steps aur solution lekhain bus. Table banane ki zaroorat nhi

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