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# STA 301 ASSIGNMENT 01 FALL 2014 DUE DATE 02/12/2014

Question 1: (Marks: 5)

a)      Construct a frequency distribution table where the class interval is 12, the number of classes is 6 and the smallest observation is 49 (lowest class limit). Also build the column of the relative frequency. The data is given below:

74, 49, 103, 95, 90, 118, 52, 88, 101, 96, 72, 56, 64, 110, 97, 59, 62, 96, 82, 65, 85, 105, 116, 91, 83, 99, 52, 76, 84, 90.

Question 2: (Marks: 5)

a)      Compute the mean deviation from the mean for the following data.

(Where Mean = 3.949)

 X f 2.8 4 3.0 15 3.2 20 3.4 47 3.6 63 3.8 78 4.0 88 4.2 69 4.4 59 4.6 35 4.8 10 5.0 8 5.2 4 500

Question 3:                                                                                                        (Marks: 3+2=5)

a)      The ages of 22 football players are listed below:

66, 73, 68, 54, 25, 38, 67, 69, 74, 53, 52, 72, 55, 75, 37, 24, 13, 12, 11, 26, 39, 23

Make a stem and leaf display for the data.

b)      Which variable (Discrete or Continuous) is more suitable in the following examples?

• The content of a bottle of fluid is quoted as 1025 ml.
• People are asked to state their age at their birthday.
• People are asked to state how many times in the last month they visited their family doctor.
• The height of trees at a nursery.

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Objective(s) of this Assignment:

• The assignment is being uploaded to build up the concepts about:
• Variable
• Frequency Distribution
• Stem and Leaf
• Measure of Dispersion

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### Replies to This Discussion

yar solve kr tu dia ha . deak ha q. no. 2

main tu confuse ho is k bare main ....

confuse kou ho . complete ha . aur correct b

yes u right

Question # 1:

Step # 1:

Class interval  = h = 12

Smallest value  = 49

No. of   classes = 6

Step # 2:

Make a lower class limit

 Class   number Lower class limit 1 49 2 49 + 12 =    61 3 61 + 12 =    73 4 73 + 12 =    85 5 85 + 12 =    97 6 97 + 12 =   109

Step # 3:

Make a upper class limit

 Class   number Lower class limit Upper class limit 1 49 60 2 49 + 12 =    61 60 + 12 =   72 3 61 + 12 =    73 72 + 12 =   84 4 73 + 12 =    85 84 + 12 =   96 5 85 + 12 =    97 96 + 12 =  108 6 97 + 12 =   109 108 + 12 =  120

Step # 4:

 Classes 49    -    60 61    -    72 73    -    84 85    -    96 97    -   108 108   -   120

Step # 5:

Make a frequency distribution table

 Classes Tally  bar Frequency Relative frequency 49    -    60 5 5/30 = 0.166667 61    -    72 4 4/30 = 0.133333 73    -    84 6 6\30 = 0.2 85    -    96 7 7/30 = 0.233333 97    -   108 5 5/30 = 0.166667 108   -   120 3 3/30 = 0.1 Total 30 Total =  1

First of all arrange the data in ascending order.i.e.

49,52,52,56,59,62,64,65,72,74,76,82,83,84,85,88,90,90,91,95,96,96,97,99,101,103, 105,110, 116,118

By adding all these values we will get the total sum of frequency i.e.

49+52+52+56+59+62+64+65+72+74+76+82+83+84+85+88+90+90+91+95+96+96+97+ 99+101+103+105+110+116+118= 2510

To calculate mean deviation we have to use this formula:

M.D=Ʃǀdiǀ

n

Question 1:                                                                                                             (Marks: 5)

a)      Construct a frequency distribution table where the class interval is 12, the number of classes is 6 and the smallest observation is 49 (lowest class limit). Also build the column of the relative frequency. The data is given below:

74, 49, 103, 95, 90, 118, 52, 88, 101, 96, 72, 56, 64, 110, 97, 59, 62, 96, 82, 65, 85, 105, 116, 91, 83, 99, 52, 76, 84, 90.

Solution:

 Classes Limit Frequency (f) Relative frequency Rf= 14ff"> 49 - 60 5 5/30 = 0.167 61 - 72 4 4/30 = 0.133 73 - 84 5 5/30 = 0.167 85 - 96 8 8/30 = 0.267 97-108 5 5/30 = 0.167 109 - 120 3 3/30 = 0.100 14f=30">

Question # 3 (a):

Stem and Leaf  Display

 Stem Leading  Digit Leaf Trailing  Digit 1 1  2  3 2 3  4 ssss 5 6 3 7  8  9 5 2  3  4 5 6 6  7  8 9 7 2  3  4 5

(b)   Which variable (Discrete or Continuous) is more suitable in the following examples?

• The content of a bottle of fluid is quoted as 1025 ml   (continuous variable)
• People are asked to state their age at their birthday.      (continuous  variable)
• People are asked to state how many times in the last month they visited their family doctor.   (discrete  variable)
• The height of trees at a nursery.    (continuous  variable)

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