STA-301 Assignment No.1 ....Idea Solution 100% Correct

[+ Abdul Rehman Aทઽα૨i]

Assalam-o-Alaikum

 

Find the attachment of solved assignment No. 1 of Sta-301....

Solved%201st%20Assignment%20of%20Sta301.xls

Kindly dont copy paste it otherwise a big ZERO is waiting for you.

 

 

Important Tips

 

Frequency distribution ka sb se easy tareeka or jaldi se calculate karny ka tareeka ye hy k ap ko jitni values di gae hain un sb ko excel me aik column me paste kr lyn.

Then sb ko select kr k sort kr lyn smallest to largest value then ap easily count kr sakty hain or ye tareeka bht short hy otherwise it will take your 15 mints in exam and question reh jay ga....

 

 

Anyone if find any mistakes in the solution then can discussion freely.....

 

[+ Abdul Rehman Aทઽα૨i]

what is class boundaries?

class boundaries = upper class - lower class / 2

here is this case 25 is upper class and 24 is lower hence

25-24/2 which is equal to 0.5

now we will deduct 0.5 from 20 and will add 0.5 to 24 to get class boundaries

for example 

our class limit is 

20-24

now we will 

20-0.5--------24+0.5

which will be 19.5---24.5 this is the method to convert class limits and class boundaries

Note:

Class interval is 5

so we will make a class from 20-24

because 20,21,22,23,24 these are five which is our limit. not 20-25 it will be 6 limit

So the correct class limit is 20-24

Now lets talk about the second question 

The same method we will use to get class boundaries 

0.7314-0.7313/2=0.0005

now we will decrease 0.00005 from 0.7312 and we will add 0.00005 to 0.7313 same like that we will make class boundaires for every class limits 

and for MODE we will take modal class

now 

What is Modal Class?

Modal class is that class in which ur maximum frequency lie. Here in this case 30 is the maximum frequecny and its class is modal class and the frequency which is exectly above 30 will be called as F1 and frequecy exct below the 30 will be called as F2

Thanks and Best Regards

Abdul Rehman Ansari 

[MCS-III]

 Abdul Rehman Ansari bhai ap ne mid point thek calculate nai kya.

[+ Abdul Rehman Aทઽα૨i]

mid point class boundaries lety hain dear class limits se nahi .....or jab ap ne mode calculate karna ho tb to class boundaries use hoti hain always....... ye solution of hinna wrong hay totaly.....Capus teacher ne jo solve karaya or smjhaya wo mery solution me dekh lo ap 

[Armghan ali sabir]

thakn's bahi ...........

[Rana Muhammad Irfan Arshad Fani]

very good dear, thanks

[+ M.Tariq Malik]

One more idea solution of STA301 Assignment No 1 Spring 2012 By Hinna

[+ Abdul Rehman Aทઽα૨i]

clas interval is 5 tariq bhai

and we uuse inclusive style in which we will make a class from 20-24

[sobia sobi]

thanxxxxxxxxxxx ide dany ka

[AbdulRahman]

defination of class interval:

Class Intervals

Class interval is the difference between the upper and lower class boundaries of any class

so we take class limit 20-25

for mor infor please check the hand outs and visit

http://wizznotes.com/mathematics/statistics/class-limits-boundaries...

[+ Abdul Rehman Aทઽα૨i]

question no 2 me class boundaries nahi bnai which is tottaly wrong

Follow the book Businees Stat Math of Sohail Afzal B.Com Part 1

[+ Abdul Rehman Aทઽα૨i]

goup data ka mode bager class boundary k nahi nikal sakta Read The STA-301 Handouts of VU page number 50

And kindly without proof kisi ko ghalat guide mat karyn ajeeeb ajeeeb solution dy k ...Thanks 

[+ Abdul Rehman Aทઽα૨i]

yes dear u r right but i tell u what i know lots jobsters who jjust download directly the idea solution and changes it a bit then submit me ne esa isi liye bola k kisi ka nuksan na ho bs