sta301 1st assignment solution by ash

[ash]

if u find any mistake so plzzzzz tell

[3908xw0d3g8s6]

I think there is some problem in you Median.............. I have calculated like that

[Miss Sunshine]

any one please give the solution of question one part (b)

[khurram shahzad]

please check your solution again because i think it is going to be wrong, the reason in mistake in your calciulation, the correct answer is 163.621

[Adnan]

Khurram bhai ap ka answer 163.621 wrong ha... Asim ka solution teek ha

[Adnan]

U can also calculate ur Geometric Mean result from calculator on this side

http://www.sengpielaudio.com/calculator-geommean.htm

[Be@ch]

q2 ma H.M k liye f/x find krna hai answer 164.862 ata hai

[khurram shahzad]

in question number 2 the calculation of cumulative frequency mean to say C.F is 190 not 180. so please check your answer before to solve it

 

[+ M.Tariq Malik]

STA301_100%_Correct_Solution

[+ M.Tariq Malik]

Fall2012_STA301_1_SOLUTION

See the attached file please 

[zia_ur_rehman]

thanks tariq bhai

[reja]

plz 2nd question ke part 1 ka median part show kr dy plz

[+ M.Tariq Malik]

Question 1:                                                                                                                   Marks: 5+2=7

 

a)   Following are the heights (in centimeters) of 45 female high school students. Prepare a frequency distribution of the data where the class width is 5, the number of classes is 6 and the smallest observation is 148. Also obtain the relative frequency and relative cumulative frequency.

 

170, 151, 154, 160, 158, 154, 171, 156, 160, 157, 160, 157, 148, 165, 158, 159, 155, 151, 152, 161, 156, 164, 156, 163, 174, 153, 170, 149, 166, 154, 166, 160, 160, 161, 154, 163, 164, 160, 148, 162, 167, 165, 158, 158, 176.

ANSWER:

Classes	(f)	r.f	r.c.f
148 - 152	6	6/45 = ans	0.133
153 - 157	11	11/45 =ans	0.377
158 - 162	14	14/45 = ans	0.688
163 - 167	9	9/45 = ans	0.888
168 - 172	3	3/45 =ans	0.955
173 - 177	2	2/45 = ans	0.999
	45

 

 

 

 

 

 

 

 

b)     Which level of measurement (scale of measurement) is suitable for the following data in each example?

i)                    The lake Saif-ul-Muluk is 10,578 feet above from the sea level. (Ratio Scale)

ii)                  If customers go to the shop for buying shoes and try different size of shoes. The sizes of shoes are 7B, 10D and 12E. (Interval Scale)

iii)                The numbering on T-shirts of players in the cricket team.  (Ordinal Scale)

iv)                The weight of the person is 68 kg. (Nominal Scale)

Question 2:                                                                                                                   Marks: 5+3=8

a)      Find the median, harmonic mean and 23^rd percentile for the following frequency distribution.

 

Class Boundaries	Frequency
145 – 150	4
150 – 155	6
155 – 160	28
160 – 165	58
165 – 170	64
170 – 175	30

Solution:

Boundaries	f	c.f
145 – 150	4	4
150 – 155	6	10
155 – 160	28	38
160 – 165	58	96
165 – 170	64	160
170 – 175	30	190

median=l + h/f(n/2− c)

l = 164,h = 5,f = 64,n = 190,c = 96

CALCULATE YOURSELF PLEASE

 

Class Boundaries	Frequency	X	1/X	F(1/X)
145 – 150	4	(145 + 150)/2	0.007	0.03
150 – 155	6	-	0.007	0.04
155 – 160	28	-	0.006	0.2
160 – 165	58	-	0.006	0.4
165 – 170	64	-	0.006	0.4
170 – 175	30	-	0.006	0.2
	190			TOTAL=

H.M =n/{∑f(1/x)}

 

CALCULATE YOURSELF PLEASE

 

 

boundaries	f	c.f
145 – 150	4	4
150 – 155	6	10
155 – 160	28	38
160 – 165	58	96
165 – 170	64	160
170 – 175	30	190

P23 = l + h/f(23n/100 − c)

l=164,h = 5,f = 64,n = 190,c = 96

CALCULATE YOURSELF PLEASE

 

b)     Explain the concept of Geometric mean? Also find the geometric mean for the following data.

18, 19, 19, 19, 19, 20, 20, 20, 20, 20, 21, 21, 21, 21, 22, 23, 24, 27, 30, 36

Solution:

x	logx
18	1.26
19	1.27
19	1.27
19	1.27
19	1.27
20	1.30
20	1.30
20	1.30
20	1.30
20	1.30
21	1.32
21	1.32
21	1.32
21	1.32
22	1.34
23	1.36
24	1.38
27	1.43
30	1.48
36	1.56
	19.46

 

g.m = log G = (∑ log X)/n

CALCULATE YOURSELF PLEASE