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Assignment No.2 (Course STA301)

Spring 2013 (Total Marks 15)

 

Deadline

Your Assignment must be uploaded/ submitted before or on

23:59, July 02, Date 2013

STUDENTS ARE STRICTLY DIRECTED TO SUBMIT THEIR ASSIGNMENT BEFORE OR BY DUE DATE. NO ASSIGNMNENT AFTER DUE DATE WILL BE ACCEPTED VIA E.MAIL).

 

Rules for Marking

It should be clear that your Assignment will not get any credit IF:

  • The Assignment submitted, via email, after due date.
  • The submitted Assignment is not found as MS Word document file.
  • There will be unnecessary, extra or irrelevant material.
  • The Statistical notations/symbols are not well-written i.e., without using MathType software.
  • The Assignment will be copied from handouts, internet or from any other student’s file. Copied material (from handouts, any book or by any website) will be awarded ZERO MARKS. It is PLAGIARISM and an Academic Crime.
  • The medium of the course is English. Assignment in Urdu or Roman languages will not be accepted.
  • Assignment means Comprehensive yet precise accurate details about the given topic quoting different sources (books/articles/websites etc.). Do not rely only on handouts. You can take data/information from different authentic sources (like books, magazines, website etc) BUT express/organize all the collected material in YOUR OWN WORDS. Only then you will get good marks.

 

 

Objective(s) of this Assignment:

 

This assignment is uploaded in order to build understanding about the properties of:

  • Binomial distribution
  • Hyper geometric distribution
  • Poisson distribution
  • Normal distribution

 

 

 

Assignment No: 2 (Lessons 28-30)

Question 1:                                                                                                                   Marks: 4+4=8

 

      a)  Suppose 4 dresses are randomly chosen without replacement from the total of 8 dresses (5 red and 3 white). Calculate the probability of getting exactly 2 red dresses out of 5 red dresses. (Solve using hypergeometric distribution)

 

 

b)   A random variable “X” following binomial distribution with n=5 and p=0.5 Calculate the mean, variance and Coefficient of Variance.

 

Question 2:                                                                                                                   Marks: 4+3=7

 

a)  One hundred passengers have made reservations for a train. If the probability that a passenger who has a reservation will not show up is 0.01, what is the probability that exactly 2 will not show up? (Use appropriate distribution)

 

b)  A certain type of car battery lasts on an average 2 years, with a standard deviation    of 0.5 year. Assuming that the battery lives are normally distributed, find the probability that a given battery will last less than 2.5 years. 

 

    

 

-END-

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Replies to This Discussion

thanks 

samra tariq gud keep it up & thanks for sharing 

Attention Students: You don’t need to go any other site for this assignment/GDB/Online Quiz solution, Because All discussed data of our members in this discussion are going from here to other sites. You can judge this at other sites yourself. So don’t waste your precious time with different links.

You don’t need to go any other site for this assignment/GDB/Online Quiz solution, Because All discussed data of our members in this discussion are going from here to other sites. You can judge this at other sites yourself. So don’t waste your precious time with different links.


so give me idea hint wegera

Please Discuss here about this assignment.Thanks

Our main purpose here discussion not just Solution

We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.

Has somebody else tried the questions? Do share your answers over here so that errors (if any) could be rectified...

Thanks...

Regards...

yes ur ans are correct !!

have you submitted? is yes please share the original file with me

b)

  1. mean: 2.5
  2. variance: 1.25
  3. coefficient of variance: 44.72%

    n=5 p =0.5 q=1-p=1-0.5=0.5

    mean= np=5(0.5)=2.5

    variance= npq= 5(0.5)(0.5)=1.25

   

    




Answer of Q1:

a) 43% (consider revising)

b)

  1. mean: 2.5
  2. variance: 1.25
  3. coefficient of variance: 44.8% (S.D=1.12)

Answer of Q2:

a) 0.1839 i.e. 18.39% (Poisson distribution)

b) 15.87% (consider revising)

Please check if I am wrong somewhere, this is just the rough solution, just to check that whether the answers are correct or not?

Thanks...

Regards...

Can you give brief explanation on your answers. I mean what formulas you used to find them.

Regards,

b)

  1. mean: 2.5
  2. variance: 1.25
  3. coefficient of variance: 44.72%

    n=5 p =0.5 q=1-p=1-0.5=0.5

    mean= np=5(0.5)=2.5

    variance= npq= 5(0.5)(0.5)=1.25

   




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